Logarithms

We are given that Let's first solve for and . Similarly, Now, using the relationship , Thus, Using the value , we get:

The correct option is (B):

Correct answer: ±3

Explanation:
Given:

Using logarithmic identity:

So,

Taking square root on both sides:

So, x = ±3. Since ±3 is not listed directly, among the options, only 3 and -3 are valid.

We know that 32 = 2 × 2 × 2 × 2 × 2 = 2⁵

Therefore, log₂ 32 = log₂ (2⁵) = 5

Conclusion:

The value of log₂ 32 is (3) 5.