Carbohydrates

Step 1: Hydrolysis of cellulose.
Cellulose, a polysaccharide, is hydrolyzed to give D-glucose units.
Thus, the correct answer is (2).

Step 1: Starch forms a deep blue complex with iodine.
Step 2: Even traces of iodine can be detected.

Step 1: Reduction of fructose gives sorbitol and mannitol.
Step 2: These differ in configuration at one chiral carbon.
Step 3: Hence they are epimers and therefore diastereomers.

Step 1: Methanolic HCl converts glucose into methyl glucoside (acetal).
Step 2: Acetals are non-reducing.
Step 3: Hence Tollen’s reagent gives no reaction.

Amylopectin and cellulose are polysaccharides with glycosidic bonds. Amylase acts on glycosidic bonds.

Step 1: Fructose is a ketohexose. On reduction, the carbonyl group (C=O) is reduced to an alcohol.
Step 2: Reduction of fructose gives two hexitols: sorbitol and mannitol.
Step 3: Sorbitol and mannitol differ in configuration at one chiral carbon (C-2). ⟹ They are epimers and hence diastereomers

Step 1: Methanolic HCl converts glucose into methyl glucoside by acetal formation.
Step 2: In methyl glucoside, the free aldehyde group is blocked.
Step 3: Tollens’ reagent gives a positive test only with free aldehyde groups. ⟹ No reaction with Tollens’ reagent

Step 1: Glycosidic linkage joins monosaccharide units. Step 2: \beginitemize • Amylopectin – α-glycosidic bonds • Cellulose – β-glycosidic bonds • Amylase – enzyme composed of amino acids but interacts with glycosidic bonds \enditemize Hence, option (D) is correct.