CET-DELHI-POLYTECHNIC SERIES Chemistry
Periodic Table
7 previous year questions.
Volume: 7 Ques
Yield: Medium
High-Yield Trend
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2019 3
2018 2
2017 Chapter Questions 7 MCQs
01
PYQ 2017
medium
chemistry ID: cet-delh
In the periodic table the position of the element still uncertain is of :
1
Lithium
2
Hydrogen
3
Helium
4
Carbon
Official Solution
Correct Option: (2)
Concept: The periodic table organizes elements based on their atomic number and recurring chemical properties. While most elements have a clearly defined position, the placement of Hydrogen has been a subject of discussion due to its unique properties. Step 1: Properties of Hydrogen
Hydrogen (H) has atomic number 1, with an electronic configuration of 1s . It exhibits properties that allow it to resemble:
Alkali Metals (Group 1):
Like alkali metals, it has one valence electron (ns ).
It can lose this electron to form a positive ion (H , a proton).
It forms similar types of oxides, halides, and sulfides.
Halogens (Group 17):
Like halogens, it is one electron short of a complete valence shell (for hydrogen, the K-shell which is full with 2 electrons). Halogens are one electron short of a p-subshell octet.
It can gain an electron to form a negative ion (H , hydride ion), similar to halogens forming halide ions (e.g., F , Cl ).
It exists as a diatomic molecule (H ), similar to halogens (F , Cl , Br , I ).
It is a non-metal, like halogens.
Group 14 (Carbon group - less common placement): Some arguments place it here due to having a half-filled valence shell and similar electronegativity to carbon, but this is not a widely accepted placement. Step 2: Common Placement and Uncertainty
Most commonly, Hydrogen is placed at the top of Group 1 (Alkali Metals) because of its 1s electron configuration.
However, it differs significantly from alkali metals: it's a gas, a non-metal, and forms covalent bonds much more readily.
Sometimes it is placed separately in the periodic table, or even occasionally above Group 17 (Halogens), to reflect its unique dual nature. This dual resemblance means its position is not as straightforward as other elements and is sometimes considered "uncertain" or anomalous. Step 3: Analyzing the options
(1) Lithium (Li): Atomic number 3 (1s 2s ). Clearly an alkali metal (Group 1). Its position is certain.
(2) Hydrogen (H): As discussed, its position is unique and debated due to its properties resembling both Group 1 and Group 17.
(3) Helium (He): Atomic number 2 (1s ). It has a completely filled K-shell, making it very unreactive. It is placed in Group 18 (Noble Gases) due to its chemical inertness, even though its valence shell configuration (1s ) technically fits Group 2 (Alkaline Earth Metals) based on s-block filling. However, its properties align with noble gases, so its position in Group 18 is well-established.
(4) Carbon (C): Atomic number 6 (1s 2s 2p ). Clearly in Group 14. Its position is certain. Of the options, Hydrogen is the element whose position in the periodic table has historically been and continues to be the most discussed and sometimes considered "uncertain" or unique.
Alkali Metals (Group 1):
Like alkali metals, it has one valence electron (ns ).
It can lose this electron to form a positive ion (H , a proton).
It forms similar types of oxides, halides, and sulfides.
Halogens (Group 17):
Like halogens, it is one electron short of a complete valence shell (for hydrogen, the K-shell which is full with 2 electrons). Halogens are one electron short of a p-subshell octet.
It can gain an electron to form a negative ion (H , hydride ion), similar to halogens forming halide ions (e.g., F , Cl ).
It exists as a diatomic molecule (H ), similar to halogens (F , Cl , Br , I ).
It is a non-metal, like halogens.
Group 14 (Carbon group - less common placement): Some arguments place it here due to having a half-filled valence shell and similar electronegativity to carbon, but this is not a widely accepted placement. Step 2: Common Placement and Uncertainty
Most commonly, Hydrogen is placed at the top of Group 1 (Alkali Metals) because of its 1s electron configuration.
However, it differs significantly from alkali metals: it's a gas, a non-metal, and forms covalent bonds much more readily.
Sometimes it is placed separately in the periodic table, or even occasionally above Group 17 (Halogens), to reflect its unique dual nature. This dual resemblance means its position is not as straightforward as other elements and is sometimes considered "uncertain" or anomalous. Step 3: Analyzing the options
(1) Lithium (Li): Atomic number 3 (1s 2s ). Clearly an alkali metal (Group 1). Its position is certain.
(2) Hydrogen (H): As discussed, its position is unique and debated due to its properties resembling both Group 1 and Group 17.
(3) Helium (He): Atomic number 2 (1s ). It has a completely filled K-shell, making it very unreactive. It is placed in Group 18 (Noble Gases) due to its chemical inertness, even though its valence shell configuration (1s ) technically fits Group 2 (Alkaline Earth Metals) based on s-block filling. However, its properties align with noble gases, so its position in Group 18 is well-established.
(4) Carbon (C): Atomic number 6 (1s 2s 2p ). Clearly in Group 14. Its position is certain. Of the options, Hydrogen is the element whose position in the periodic table has historically been and continues to be the most discussed and sometimes considered "uncertain" or unique.
02
PYQ 2017
medium
chemistry ID: cet-delh
Glucose is broken down to 3-carbon compound called :
1
Oxaloacetate
2
Citrate
3
Pyruvate
4
Acetate
Official Solution
Correct Option: (3)
Concept: The initial stage of cellular respiration, common to both aerobic and anaerobic respiration, is glycolysis. In this process, a glucose molecule is broken down. Step 1: Understanding Glycolysis
Glycolysis is a metabolic pathway that occurs in the cytoplasm of cells. It involves a series of enzymatic reactions that convert one molecule of glucose (a 6-carbon sugar) into two molecules of a 3-carbon compound. This process also produces a net gain of ATP (energy currency) and NADH (an electron carrier). Step 2: The Product of Glycolysis
The 6-carbon glucose molecule ( ) is split and oxidized during glycolysis to form two molecules of pyruvate (also known as pyruvic acid).
Pyruvate is a 3-carbon compound with the chemical formula (for the ion) or (for the acid). Step 3: Analyzing the options
(1) Oxaloacetate: This is a 4-carbon molecule that is an intermediate in the Citric Acid Cycle (Krebs cycle).
(2) Citrate: This is a 6-carbon molecule that is formed in the first step of the Citric Acid Cycle when acetyl-CoA combines with oxaloacetate.
(3) Pyruvate: Correct. Glucose (6-carbon) is broken down into two molecules of pyruvate (3-carbon each) during glycolysis.
(4) Acetate: This is a 2-carbon molecule (often as acetyl-CoA, which is formed from pyruvate before entering the Citric Acid Cycle in aerobic respiration). Therefore, glucose is broken down to the 3-carbon compound called pyruvate.
(1) Oxaloacetate: This is a 4-carbon molecule that is an intermediate in the Citric Acid Cycle (Krebs cycle).
(2) Citrate: This is a 6-carbon molecule that is formed in the first step of the Citric Acid Cycle when acetyl-CoA combines with oxaloacetate.
(3) Pyruvate: Correct. Glucose (6-carbon) is broken down into two molecules of pyruvate (3-carbon each) during glycolysis.
(4) Acetate: This is a 2-carbon molecule (often as acetyl-CoA, which is formed from pyruvate before entering the Citric Acid Cycle in aerobic respiration). Therefore, glucose is broken down to the 3-carbon compound called pyruvate.
03
PYQ 2018
medium
chemistry ID: cet-delh
Which of the following is a member of the Halogen family ?
1
Cl
2
Ca
3
Cu
4
Cr
Official Solution
Correct Option: (1)
Concept: The Halogen family is a specific group of elements in the periodic table known for their characteristic properties. Step 1: Identifying the Halogen Group
The Halogens are the elements found in Group 17 (or VIIA) of the periodic table.
The members of the Halogen family are: % Option
(\) Fluorine (F)
% Option
(]) Chlorine (Cl)
% Option
(^) Bromine (Br)
% Option
(_) Iodine (I)
% Option
(`) Astatine (At) - radioactive
% Option
(a) Tennessine (Ts) - synthetic, radioactive These elements are highly reactive nonmetals and readily form salts by reacting with metals (the name "halogen" means "salt-former"). Step 2: Analyzing the options % Option
(b) (1) Cl (Chlorine): Chlorine is a member of Group 17, the Halogen family.
% Option
(c) (2) Ca (Calcium): Calcium is an alkaline earth metal, found in Group 2 of the periodic table.
% Option
(d) (3) Cu (Copper): Copper is a transition metal, found in Group 11 of the periodic table.
% Option
(e) (4) Cr (Chromium): Chromium is a transition metal, found in Group 6 of the periodic table. Step 3: Identifying the Halogen
From the list, Chlorine (Cl) is the only element that belongs to the Halogen family.
04
PYQ 2018
medium
chemistry ID: cet-delh
The metal most commonly used for making filament of an electric bulb is :
1
Tungsten
2
Copper
3
Silver
4
Aluminium
Official Solution
Correct Option: (1)
Concept: The filament of an incandescent electric bulb needs to have specific properties to function effectively: it must glow brightly when heated by electric current and withstand very high temperatures without melting or quickly degrading. Step 1: Desired Properties of a Bulb Filament Material % Option
(f) High Melting Point: The filament heats up to incandescence (glowing hot, typically over ). The material must not melt at these operating temperatures.
% Option
(g) High Resistivity: A higher resistivity means that for a given current, more heat ( ) is generated in a reasonably sized filament. If the resistivity were too low, a very long and thin wire would be needed.
% Option
(h) Ductility: The ability to be drawn into thin wires.
% Option
(i) Low Vapor Pressure at High Temperatures: The material should not evaporate quickly at operating temperatures, as this would thin the filament and shorten its life, as well as blacken the bulb.
% Option
(j) Sufficient Mechanical Strength at High Temperatures. Step 2: Analyzing the options % Option
(k) (1) Tungsten (W): % Option
(l) Extremely High Melting Point: Approximately , the highest of all metals. This is its most crucial property for use as a filament.
% Option
(m) High resistivity (though lower than some alloys, it's suitable).
% Option
(n) Good ductility.
% Option
(o) Relatively low vapor pressure at high temperatures. Tungsten meets these requirements exceptionally well and is the standard material for incandescent bulb filaments.
% Option
(p) (2) Copper (Cu): Melting point is relatively low ( ). It would melt long before reaching incandescent temperatures. It also has very low resistivity, making it unsuitable for a compact filament.
% Option
(q) (3) Silver (Ag): Melting point is low ( ). Would melt easily. Excellent conductor (low resistivity), also not ideal for this purpose.
% Option
(r) (4) Aluminium (Al): Melting point is low ( ). Would melt very easily. Good conductor (low resistivity). Step 3: Identifying the most suitable metal
Due to its exceptionally high melting point and other favorable properties at high temperatures, Tungsten is the metal most commonly used for making the filament of an electric incandescent bulb.
05
PYQ 2018
medium
chemistry ID: cet-delh
Which of the following is the most electronegative element in the periodic table ?
1
Oxygen
2
Nitrogen
3
Flourine
4
Chlorine
Official Solution
Correct Option: (3)
Concept: Electronegativity is a measure of the tendency of an atom to attract a bonding pair of electrons towards itself when it is part of a chemical bond. Step 1: Trends in Electronegativity in the Periodic Table % Option
(H) Across a Period (Left to Right): Electronegativity generally increases. This is because the number of protons (nuclear charge) increases, pulling the bonding electrons more strongly, while the electrons are added to the same principal energy level.
% Option
(I) Down a Group (Top to Bottom): Electronegativity generally decreases. This is because the bonding electrons are in higher energy levels, further from the nucleus, and are shielded by more inner electron shells, reducing the nucleus's attraction for them. As a result of these trends, the most electronegative elements are found in the upper right-hand corner of the periodic table (excluding noble gases, which generally don't form bonds readily or have conventionally defined electronegativity values in the same scale). Step 2: Identifying the Most Electronegative Element
Fluorine (F) is located at the top of Group 17 (Halogens) and in the second period. Due to its position, it has the highest electronegativity value of all elements. On the Pauling scale (a common scale for electronegativity), fluorine is assigned a value of 3.98 (often rounded to 4.0). Step 3: Comparing the electronegativity of the given options
Approximate Pauling electronegativity values: % Option
(J) (1) Oxygen (O): (Second most electronegative)
% Option
(K) (2) Nitrogen (N): (Third/Fourth most electronegative, close to Chlorine)
% Option
(L) (3) Fluorine (F): (Most electronegative)
% Option
(M) (4) Chlorine (Cl): (Third/Fourth most electronegative, close to Nitrogen) The order of electronegativity for these common highly electronegative elements is: F>O>Cl N. Therefore, Fluorine is the most electronegative element in the periodic table. (Note: The spelling in the option is "Flourine", the correct spelling is "Fluorine").
06
PYQ 2019
medium
chemistry ID: cet-delh
Triads rule was given by:
1
Rutherford
2
Dobereiner
3
New Lands
4
Rutherford and New Land
Official Solution
Correct Option: (2)
Step 1: Understand the Triads Rule. The Triads Rule is a concept in chemistry that was proposed by Johann Wolfgang DΓΆbereiner in the early 19th century. DΓΆbereiner observed that certain elements could be grouped into triads of three elements with similar properties, where the atomic mass of the middle element in each triad was approximately the average of the atomic masses of the other two elements. Step 2: Analyze Each Option.
Option (1): Rutherford β Incorrect, as Rutherford is known for his work on atomic structure, not the Triads Rule.
Option (2): Dobereiner β Correct, as DΓΆbereiner is credited with proposing the Triads Rule.
Option (3): New Lands β Incorrect, as this is not a recognized name associated with the Triads Rule.
Option (4): Rutherford and New Land β Incorrect, as neither Rutherford nor "New Land" is associated with the Triads Rule. Step 3: Final Answer. $ $
Option (1): Rutherford β Incorrect, as Rutherford is known for his work on atomic structure, not the Triads Rule.
Option (2): Dobereiner β Correct, as DΓΆbereiner is credited with proposing the Triads Rule.
Option (3): New Lands β Incorrect, as this is not a recognized name associated with the Triads Rule.
Option (4): Rutherford and New Land β Incorrect, as neither Rutherford nor "New Land" is associated with the Triads Rule. Step 3: Final Answer. $ $
07
PYQ 2019
medium
chemistry ID: cet-delh
Mendeleev's Modren periodic law is based on :
1
Atomic mass
2
Atomic Number
3
No. of Nutron's
4
Atomic mass and atomic Number
Official Solution
Correct Option: (1)
Step 1: Understand Mendeleev's original Periodic Law.
Dmitri Mendeleev formulated the periodic law stating that the properties of elements are a periodic function of their atomic masses. He arranged elements in his periodic table primarily based on increasing atomic mass. Step 2: Differentiate between Mendeleev's and the Modern Periodic Law.
The question specifically asks about "Mendeleev's Modren periodic law". This phrasing is slightly ambiguous. The "Modern Periodic Law" (as established later by Moseley) is based on atomic number. However, if it refers to "Mendeleev's" law, it is based on atomic mass. Given the options, it's highly likely it refers to Mendeleev's original formulation. Step 3: Evaluate the given options.
(1) Atomic mass: This is the basis of Mendeleev's original periodic law.
(2) Atomic Number: This is the basis of the Modern Periodic Law (developed after Mendeleev's work).
(3) No. of Nutron's (Neutrons): The number of neutrons (and thus mass number) is related to atomic mass, but Mendeleev didn't explicitly use neutron count as the basis.
(4) Atomic mass and atomic Number: While both are important properties, Mendeleev's law was specifically based on atomic mass. Step 4: Conclude the correct basis for Mendeleev's periodic law.
Mendeleev's periodic law is based on atomic mass. (1) Atomic mass
Dmitri Mendeleev formulated the periodic law stating that the properties of elements are a periodic function of their atomic masses. He arranged elements in his periodic table primarily based on increasing atomic mass. Step 2: Differentiate between Mendeleev's and the Modern Periodic Law.
The question specifically asks about "Mendeleev's Modren periodic law". This phrasing is slightly ambiguous. The "Modern Periodic Law" (as established later by Moseley) is based on atomic number. However, if it refers to "Mendeleev's" law, it is based on atomic mass. Given the options, it's highly likely it refers to Mendeleev's original formulation. Step 3: Evaluate the given options.
(1) Atomic mass: This is the basis of Mendeleev's original periodic law.
(2) Atomic Number: This is the basis of the Modern Periodic Law (developed after Mendeleev's work).
(3) No. of Nutron's (Neutrons): The number of neutrons (and thus mass number) is related to atomic mass, but Mendeleev didn't explicitly use neutron count as the basis.
(4) Atomic mass and atomic Number: While both are important properties, Mendeleev's law was specifically based on atomic mass. Step 4: Conclude the correct basis for Mendeleev's periodic law.
Mendeleev's periodic law is based on atomic mass. (1) Atomic mass