Electromagnetic Waves

We are given an electromagnetic wave incident at normal incidence on a slab with two different materials. The refractive indices of the two materials are and . The refractive index of the vacuum is . The electric field amplitude of the wave changes due to the change in the refractive index when the wave passes from one medium to another. For a wave incident at an angle of , the relationship between the electric field amplitude in two different media can be given by the formula: where is the electric field amplitude in the first medium, and are the refractive indices of the respective mediums, and is the angle of incidence (which is in this case). - From the given wave equation , the initial electric field amplitude is 8 V cm .
- The refractive index for the first material, and for the second material. - The angle of incidence , and .
Using the formula, the electric field amplitude in region 2 becomes: Thus, the electric field amplitude in region 2 is approximately 11 V cm and the final value after considering the other factors is V cm . Therefore, the correct answer is (A) 11, 1.6.

The correct option is (C) :The reflected wave is polarized perpendicular to the plane of incidence