Laws Of Chemical Combinations

For first oxide, Moles of oxygen

%3D%5Cfrac%7B22%7D%7B16%7D%3D1.375

, Moles of

F%20e%3D%5Cfrac%7B78%7D%7B56%7D%3D1.392

Simpler molar ratio,

%5Cfrac%7B1.375%7D%7B1.375%7D%3D1%2C%20%5Cfrac%7B1.392%7D%7B1.375%7D%3D1

%5Ctherefore

The formula of first oxide is FeO. Similarly for second oxide, Moles of oxygen

%3D%5Cfrac%7B30%7D%7B16%7D%3D1.875

Moles of

F%20e%3D%5Cfrac%7B70%7D%7B56%7D%3D1.25

Simpler molar ratio

%3D%5Cfrac%7B1.875%7D%7B1.25%7D%3D1.5%2C%20%5Cfrac%7B1.25%7D%7B1.25%7D%3D1

%5Ctherefore

The formula of second oxide is

Fe%20_%7B2%7D%20O%20_%7B3%7D

. Suppose in both the oxides, iron reacts with

x%20g

oxygen.

%5Ctherefore

Equivalent weight of

Fe

FeO

%3D%5Cfrac%7B%5Ctext%20%7B%20weight%20of%20%7D%20Fe%20_%7B%5Ctext%20%7BII%20%7D%7D%7D%7B%5Ctext%20%7B%20weight%20of%20oxygen%20%7D%7D%20%5Ctimes%208

%5Cfrac%7B56%7D%7B2%7D%3D%5Cfrac%7B%5Ctext%20%7B%20weight%20of%20%7D%20Fe%20_%7B%5Ctext%20%7BII%20%7D%7D%7D%7Bx%7D%20%5Ctimes%208

%5Ctherefore

Equivalent weight of

Fe

Fe%20_%7B2%7D%20O%20_%7B2%7D%3D%5Cfrac%7B%5Ctext%20%7B%20weight%20of%20%7D%20Fe%20_%7B%20III%20%7D%7D%7B%5Ctext%20%7B%20weight%20of%20oxygen%20%7D%7D%20%5Ctimes%208

%5Cfrac%7B56%7D%7B3%7D%3D%5Cfrac%7B%5Ctext%20%7B%20weight%20of%20Fe%20%7D_%7B%5Ctext%20%7BIII%20%7D%7D%7D%7Bx%7D%20%5Ctimes%208%20.%20%5Ctext%20%7B..(ii)%20%7D

From E (i) and (ii),

%5Cfrac%7B%5Ctext%20%7B%20weight%20of%7D%20Fe_%7BII%7D%7D%7B%5Ctext%20%7B%20weight%20of%7D%20Fe_%7BII%7D%7D%3D%5Cfrac%7B3%7D%7B2%7D

Chapter Questions
1 MCQs