Friction

To determine the acceleration of the block, we follow these steps:

Since the surface is frictionless, only the horizontal component of the force causes acceleration.
Given: force $F%20%3D%2020%20%5C%2C%20%5Ctext%7BN%7D$ , angle $%5Ctheta%20%3D%2030%5E%5Ccirc$ , mass $m%20%3D%205%20%5C%2C%20%5Ctext%7Bkg%7D$ .
Calculate the horizontal force component: $F_x%20%3D%20F%20%5Ccos%20%5Ctheta%20%3D%2020%20%5Ctimes%20%5Ccos%2030%5E%5Ccirc.$
Since $%5Ccos%2030%5E%5Ccirc%20%3D%20%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D%20%5Capprox%200.866$ : $F_x%20%3D%2020%20%5Ctimes%200.866%20%5Capprox%2017.32%20%5C%2C%20%5Ctext%7BN%7D.$
Apply Newton’s second law: $a%20%3D%20%5Cfrac%7BF_x%7D%7Bm%7D$ . $a%20%3D%20%5Cfrac%7B17.32%7D%7B5%7D%20%5Capprox%203.464%20%5C%2C%20%5Ctext%7Bm%2Fs%7D%5E2.$
Round to two decimal places: $3.464%20%5Capprox%203.46%20%5C%2C%20%5Ctext%7Bm%2Fs%7D%5E2.$
Match with options: 3.46 m/s² corresponds to option (A).

Thus, the correct answer is:

%5Cboxed%7B3.46%20%5C%2C%20%5Ctext%7Bm%2Fs%7D%5E2%7D

Chapter Questions
1 MCQs