Straight Lines

Given, and Let and
Then,

and

Now, centroid

Given, straight lines
and are mutually perpendicular.
Therefore,

Midpoint of

Midpoint of
and mid point of

is the triangle whose centroid is to be determined.

Centroid of

is

Given, lines are
and

and
Here,





Hence, all the three sides of are equal. Therefore, the triangle is equilateral.

The correct answer is A:
Given lines, ..(i)
..(ii)
Intersection point of these line is

and

Intersection point is
.
Now, the equation of the line which passes through the points
and .
⇒

Given equation of line,
..(i)
Now, moment of the force

The given equation ..(i)
represent the point of straight line, if
where ..(ii)
Comparing E (i) with the following equation

We get,
From E (ii),

Given points are and . M is the mid-point of AB. Coordinates of Point Q divides AB externally in the ration of Day The coordinates of Q



Now, length

We have,
is the image of w.r.t. line
So, mid-point of i.e., will lie on line

Slope o f

Since is perpendicular to
Slope of line
Thus equation of line passing through and having slope is given by