Electromagnetic Spectrum

The wavelength $%5Clambda$ of a spectral line in the hydrogen atom can be determined using the Rydberg formula: $%5Cfrac%7B1%7D%7B%5Clambda%7D%20%3D%20R_H%20%5Cleft(%20%5Cfrac%7B1%7D%7Bn_1%5E2%7D%20-%20%5Cfrac%7B1%7D%7Bn_2%5E2%7D%20%5Cright)$ where $R_H%20%3D%201.097%20%5Ctimes%2010%5E7%20%5C%2C%20%7Bm%7D%5E%7B-1%7D$ is the Rydberg constant, and $n_1$ and $n_2$ are the principal quantum numbers, with $n_1%3Cn_2$ . For the first line in the Balmer series ( $n_1%20%3D%202%2C%20n_2%20%3D%203$ ): $%5Cfrac%7B1%7D%7B%5Clambda_1%7D%20%3D%20R_H%20%5Cleft(%20%5Cfrac%7B1%7D%7B2%5E2%7D%20-%20%5Cfrac%7B1%7D%7B3%5E2%7D%20%5Cright)%20%3D%20R_H%20%5Cleft(%20%5Cfrac%7B1%7D%7B4%7D%20-%20%5Cfrac%7B1%7D%7B9%7D%20%5Cright)$ $%5Clambda_1%20%3D%20%5Cfrac%7B1%7D%7BR_H%20%5Cleft(%20%5Cfrac%7B5%7D%7B36%7D%20%5Cright)%7D%20%3D%206.56%20%5Ctimes%2010%5E%7B-7%7D%20%5C%2C%20%7Bm%7D%20%3D%20656%20%5C%2C%20%7Bnm%7D$ For the second line ( $n_1%20%3D%202%2C%20n_2%20%3D%204$ ): $%5Cfrac%7B1%7D%7B%5Clambda_2%7D%20%3D%20R_H%20%5Cleft(%20%5Cfrac%7B1%7D%7B2%5E2%7D%20-%20%5Cfrac%7B1%7D%7B4%5E2%7D%20%5Cright)%20%3D%20R_H%20%5Cleft(%20%5Cfrac%7B1%7D%7B4%7D%20-%20%5Cfrac%7B1%7D%7B16%7D%20%5Cright)$ $%5Clambda_2%20%3D%20%5Cfrac%7B1%7D%7BR_H%20%5Cleft(%20%5Cfrac%7B3%7D%7B16%7D%20%5Cright)%7D%20%3D%204.86%20%5Ctimes%2010%5E%7B-7%7D%20%5C%2C%20%7Bm%7D%20%3D%20486%20%5C%2C%20%7Bnm%7D$

High-Yield Trend

Chapter Questions
1 MCQs

Official Solution

Electromagnetic Spectrum

High-Yield Trend

Chapter Questions 1 MCQs

Official Solution

Chapter Questions
1 MCQs