Puzzle

This is a logic puzzle that requires creating a table to track the properties of each book. The properties are: Cover Colour, Age, and Subject.

Let's list the information given: 1. Green Cover: B, C, E, F. This means Yellow Cover: A, D. 2. New: A, B, D. This means Old: C, E, F. 3. Law: A, B, C. This means Medical: D, E, F.

The question asks for books that satisfy three conditions simultaneously: 1. Must be Old. (The candidates are C, E, F). 2. Must be Medical extracts. (The candidates are D, E, F). 3. Must have Green covers. (The candidates are B, C, E, F).

We need to find the books that are present in all three of these candidate lists. - List 1 (Old): {C, E, F} - List 2 (Medical): {D, E, F} - List 3 (Green): {B, C, E, F} The common elements in all three lists are E and F.

Let's solve the scheduling puzzle for the 6 hours. Let the hours be H1, H2, H3, H4, H5, H6.

Let's test the two possible break positions.

Case 1: Break is in H4.
Schedule: _, _, _, BREAK, _, _.
The pairs BD and AE must fit into the remaining slots.
- If BD is at H1-H2, AE must be at H5-H6. Schedule: B, D, _, BREAK, A, E. The remaining drama is C. So, C is at H3.
Final Schedule: B, D, C, BREAK, A, E. Let's check all clues.
- Starts with B (not A) - OK. Ends with E (not C) - OK.
- D follows B - OK.
- A is not after D - OK.
- A precedes E - OK.
This is a valid schedule. The break is in H4.
Case 2: Break is in H3.
Schedule: _, _, BREAK, _, _, _.
The pairs BD and AE must fit.
- If BD is at H1-H2, AE must be at H4-H5 or H5-H6.
- AE at H4-H5: B, D, BREAK, A, E, _. C is at H6. This violates Clue 2 (Cannot end with C). Invalid.
- AE at H5-H6: B, D, BREAK, _, A, E. C is at H4. Schedule: B, D, BREAK, C, A, E. This is a valid schedule. The break is in H3.
- If AE is at H1-H2: Cannot start with A (Clue 2). Invalid.
- If BD is at H4-H5: _, _, BREAK, B, D, _. AE must be at H1-H2
(invalid) or H5-H6. No, H5 is taken. Must be at H1-H2 which is invalid.
- If BD is at H5-H6: _, _, BREAK, _, B, D. AE must be at H1-H2 (invalid) or H4-H5. No H5 is taken.
We have two possible schedules: 1. B, D, C, BREAK(H4), A, E
2. B, D, BREAK(H3), C, A, E
The question seems ambiguous as both 3rd and 4th hour are possible break hours. Let's re-read the clues.
Clue (1) A break of 1 hour has to be taken in third or four hour. This is a typo, it should be 'fourth hour'. Let's assume the question meant "in the third or fourth hour slot".
Let's re-read clue (4): "A cannot be done immediately after D". In schedule 1: (C is after D, A is after break). OK.
In schedule 2: (C is after break, A is after C). OK.
The problem seems to have two solutions. This is common in flawed exam questions. However, often there is a subtle interpretation. Let's assume the question is well-posed and I missed something.
Let's revisit my logic for Case 2.
Schedule: _, _, BREAK, _, _, _ (Break is H3).
- BD must be H1-H2. Schedule: B, D, BREAK, _, _, _.
- AE must fit. Cannot be H4-H5 because then C is at H6 (not allowed).
- Must be H5-H6. Schedule: B, D, BREAK, _, A, E. C is at H4. This is B, D, BREAK, C, A, E. It's a valid solution.
Wait, let's look at the subsequent questions.
32. Which drama to be staged first? In both solutions, B is first.
33. Which drama is staged immediately after the break? In solution 1, it's A. In solution 2, it's C.
34. Which drama after D? In solution 1, it's C. In solution 2, it's the break.
Given the likely single-answer nature, let's re-examine.
Let's re-assume the first valid schedule is the intended one: B, D, C, BREAK, A, E. Here the break is in the 4th hour.
The other valid schedule is: B, D, BREAK, C, A, E. Here the break is in the 3rd hour.
The question "Which hour is a break hour?" is fundamentally ambiguous as both 3rd and 4th are possibilities according to the rules. However, if we look at the provided OCR answer `Ans:d` which maps to `(d) 3rd`, then the intended schedule must be the second one.
Intended Schedule: B, D, BREAK, C, A, E.
Break hour is the 3rd hour.

Based on the analysis for the previous question, we have to determine the start of the schedule.
The constraints are:

• Cannot start with A (Clue 2).
• Must contain the consecutive pairs BD and AE. If the schedule starts with the AE pair, it violates Clue 2.

If the schedule starts with C, D, or E, it's difficult to fit the BD and AE pairs.
Let's try starting with B. If B is first, D must be second (from BD pair). Schedule: B, D, _, _, _, _.
This start is consistent with both valid schedules we found in the previous question.
Schedule 1: B, D, C, BREAK, A, E
Schedule 2: B, D, BREAK, C, A, E
In all possible valid arrangements, the first drama to be staged is B.

From the analysis in question 31, we found two possible schedules:

1. Schedule with break at H4: B, D, C, BREAK, A, E. Here, the drama after the break is A.
2. Schedule with break at H3: B, D, BREAK, C, A, E. Here, the drama after the break is C.

Option (C) is "A". Option (B) is "None of these". The actual drama after the break could be C. If the intended schedule is the second one (B, D, BREAK, C, A, E), then the drama after the break is C. This is not listed as an option. Therefore, the answer would be "None of these".

Let's re-read the options carefully.
(a) D, (c) A, (d) B. The correct answer could be C. Since C is not an option, the answer is (b) None of these.
The OCR `Ans:b` matches this logic. This implies the intended schedule was B, D, BREAK(H3), C, A, E.

Let's go through the exchanges and track who received the messages:
1. Dr. Anand sends a message to Dr. Beena and Dr. Chirag.

- Dr. Chirag receives a message from Dr. Anand (1 message).
- Dr. Beena receives a message from Dr. Anand (1 message).
2. Dr. Beena replies only to Dr. Anand.
- Dr. Anand receives a reply from Dr. Beena (1 message).
3. Dr. Anand sends a reminder message to who did not reply. - Dr. Chirag does not reply, so he receives another reminder message from Dr. Anand (1 message).
4. Dr. Chirag sends a message to Dr. Dinesh and Dr. Elango. - Dr. Dinesh receives a message from Dr. Chirag (1 message).
- Dr. Elango receives a message from Dr. Chirag (1 message).
5. While replying to Dr. Chirag, Dr. Dinesh accidentally sends a "Reply All."
- Dr. Anand receives a message from Dr. Dinesh (1 message).
- Dr. Beena receives a message from Dr. Dinesh (1 message).
- Dr. Chirag receives a message from Dr. Dinesh (1 message).
6. Dr. Elango, having received Dr. Chirag's message, sends a message to Dr. Beena.
- Dr. Beena receives a message from Dr. Elango (1 message).
Now, let's count the total number of messages received by each person:

- Dr. Chirag: 1 message from Dr. Anand + 1 reminder message from Dr. Anand + 1 message from Dr. Dinesh + 1 message from Dr. Dinesh (Reply All) = 4 messages
- Dr. Dinesh: 1 message from Dr. Chirag + 1 message from Dr. Dinesh (Reply All) = 2 messages
- Dr. Anand: 1 message from Dr. Beena + 1 message from Dr. Dinesh (Reply All) = 2 messages
- Dr. Beena: 1 message from Dr. Anand + 1 message from Dr. Elango + 1 message from Dr. Dinesh (Reply All) = 3 messages
- Dr. Elango: 1 message from Dr. Chirag = 1 message
The person who received the most messages directly is Dr. Chirag, with 4 messages. Thus, the correct answer is option (a).