Atomic Structure

The energy of an electron in the nth orbit is given by:
The energy in the first orbit ( ) is: The energy in the fourth orbit ( ) is: The energy required to transfer the electron from the first orbit to the fourth orbit is:

Step 1: Analyze the given data for element A.
The atomic weight of A is given as 52.
The vapor density of A's chloride is 79.
We can use the vapor density to find the molar mass of A's chloride.
Vapor density is related to the molar mass by the equation: Therefore, the molar mass of A's chloride is:
Step 2: Determine the molar mass of A's chloride.
The molar mass of A's chloride is the sum of the atomic mass of A and the atomic mass of chlorine (Cl): The atomic weight of chlorine is 106, confirming the molar mass of A's chloride.
Step 3: Calculate the atomic weight of B using oxide data.
The oxide of B contains 47.1% oxygen by mass. This means that the remaining 52.9% is the mass of element B.
Let the molar mass of B oxide be . The mass of oxygen in the oxide is given by:
Since the molar mass of oxygen is 16, we can calculate the mass of oxygen in the oxide: Thus, the molar mass of B oxide is:
Step 4: Conclusion.
The molar mass of B oxide is 34, and since the oxide contains one atom of B, the atomic weight of B is approximately 24.