Wave Optics

Step 1: Use the formula for fringe width in Young's double slit experiment.
The fringe width ( $%5Cbeta$ ) in Young's double slit experiment is given by:
$%5Cbeta%20%3D%20%5Cfrac%7B%5Clambda%20D%7D%7Bd%7D$ where: $%5Clambda$ is the wavelength of light, $D$ is the distance of the screen from the slits, $d$ is the slit separation.
Step 2: Plug in the given values.

We are given:
$%5Clambda%20%3D%20620%20%5C%2C%20%5Ctext%7Bnm%7D%20%3D%20620%20%5Ctimes%2010%5E%7B-9%7D%20%5C%2C%20%5Ctext%7Bm%7D$ , $d%20%3D%200.3%20%5C%2C%20%5Ctext%7Bmm%7D%20%3D%200.3%20%5Ctimes%2010%5E%7B-3%7D%20%5C%2C%20%5Ctext%7Bm%7D$ , $%5Cbeta%20%3D%201.3%20%5C%2C%20%5Ctext%7Bmm%7D%20%3D%201.3%20%5Ctimes%2010%5E%7B-3%7D%20%5C%2C%20%5Ctext%7Bm%7D$ . Rearrange the formula to find $D$ : $D%20%3D%20%5Cfrac%7B%5Cbeta%20d%7D%7B%5Clambda%7D$ Substitute the values: $D%20%3D%20%5Cfrac%7B(1.3%20%5Ctimes%2010%5E%7B-3%7D)%20%5Ctimes%20(0.3%20%5Ctimes%2010%5E%7B-3%7D)%7D%7B620%20%5Ctimes%2010%5E%7B-9%7D%7D%20%5C%2C%20%5Ctext%7Bm%7D$ $D%20%3D%206.29%20%5C%2C%20%5Ctext%7Bm%7D$
Step 3: Conclusion.
Thus, the distance of the screen from the source is 6.29 m.
Conclusion:
The correct answer is (B) 6.29 m.

Step 1: Use the formula for the number of images produced by two mirrors.
The number of images

n

produced by two plane mirrors is
given by the formula:

n%20%3D%20%5Cfrac%7B360%5E%5Ccirc%7D%7B%5Ctheta%7D%20-%201

where

%5Ctheta

is the angle between the mirrors.
Step 2: Apply the initial condition.
Initially, 5 images are produced, so:

%5Cfrac%7B360%5E%5Ccirc%7D%7B%5Ctheta%7D%20-%201%20%3D%205

%5Cfrac%7B360%5E%5Ccirc%7D%7B%5Ctheta%7D%20%3D%206%20%5Cquad%20%5CRightarrow%20%5Cquad%20%5Ctheta%20%3D%2060%5E%5Ccirc

Step 3: Change the angle.
Now, the angle is decreased by 30°, so the new angle is:

%5Ctheta'%20%3D%2060%5E%5Ccirc%20-%2030%5E%5Ccirc%20%3D%2030%5E%5Ccirc

Step 4: Calculate the new number of images.
Using the formula for the new angle:

n'%20%3D%20%5Cfrac%7B360%5E%5Ccirc%7D%7B30%5E%5Ccirc%7D%20-%201%20%3D%2012%20-%201%20%3D%2011

Step 5: Conclusion.
Thus, the number of images will be 11.
Conclusion:
The correct answer is (C) 11.

About Wave Optics - TRIPURA-JEE

Wave Optics is a vital chapter for TRIPURA-JEE aspirants. Mastering the concepts covered in this chapter is essential for securing a top rank.

By rigorously practicing the previous year questions associated with this chapter, you can identify high-yield topics, understand the examiner's perspective, and boost your confidence during the actual exam.

Frequently Asked Questions

Why focus on Wave Optics PYQs?

Analyzing PYQs for this specific chapter reveals the most frequently tested concepts and the typical complexity of questions, allowing you to tailor your study plan efficiently.

How to best use this analysis?

Review the topic breakdown to see which sub-topics within Wave Optics carry the most weight. Then, tackle the questions iteratively to solidify your understanding.

High-Yield Trend

Chapter Questions
2 MCQs

Official Solution

Official Solution

About Wave Optics - TRIPURA-JEE

Frequently Asked Questions

Why focus on Wave Optics PYQs?

How to best use this analysis?

Wave Optics

High-Yield Trend

Chapter Questions 2 MCQs

Official Solution

Official Solution

About Wave Optics - TRIPURA-JEE

Frequently Asked Questions

Why focus on Wave Optics PYQs?

How to best use this analysis?

Chapter Questions
2 MCQs