Nernst Equation

(i) $Zn%20%5Cleft%7C%20Zn%20%5E%7B2%2B%7D(1%20M%20)%20%5C%7C%20Ag%20%5E%7B%2B%7D(%20lM%20)%5Cright%7C%20Ag$
$Zn%20%5Cleft%7C%20Zn%20%5E%7B2%2B%7D(1%20M%20)%20%5C%7C%20Ag%20%5E%7B%2B%7D(1%20M%20)%5Cright%7C%20Ag$

given $E%20_%7B%20Zn%20%5E%7B2%2B%7D%20%2F%20Zn%20%7D%5E%7B%5Ccirc%7D%3D-0.762$
$E%20_%7B%20Ag%20%5E%7B%2B%7D%20%2F%20Ag%20%7D%5E%7B%5Ccirc%7D%3D0.799$

From Nernst equation,

$E%20%3D%20E%20%5E%7B%5Ccirc%7D-%5Cfrac%7B0.059%20l%20%7D%7B%20n%20%7D%20%5Clog%20%5Cleft%5B%5Cfrac%7B%5Ctext%20%7B%20Products%20%7D%7D%7B%5Ctext%20%7B%20Reactants%20%7D%7D%5Cright%5D$

Cell reaction for the given cell is

$Zn%20%2B2%20Ag%20%5E%7B%2B%7D%20%5Clongrightarrow%20Zn%20%5E%7B2%2B%7D%2B2%20Ag$
$E%20%3DE%20%5E%7B%5Ccirc%7D%7B%20%7D_%7B%20Ag%20%7D%5E%7B%2B%7D%20%2F%20Ag%20%5E%7B-%7D%20E%20%5E%7B%5Ccirc%7D%20zn%20%5E%7B2%2B%7D%20%2F%20Zn%20-%5Cfrac%7B0.059%20l%20%7D%7B2%7D%20%5Clog%20%5Cfrac%7B%20Zn%20%5E%7B2%2B%7D%7D%7B%5Cleft(%20Ag%20%5E%7B%2B%7D%5Cright)%5E%7B2%7D%7D$
$E%20%3D%200.799-(-0.762)-%5Cfrac%7B0.0591%7D%7B2%7D%20%5Clog%20%5Cleft(%5Cfrac%7B1%7D%7B%20l%20%5E%7B2%7D%7D%5Cright)$
$E%20%3D%201.569%5C%2C%20V$

(ii) $Cu%20%5Cleft%7C%20Cu%20%5E%7B2%2B%7D(1%20M%20)%20%5C%7C%20Ag%20%5E%7B%2B%7D(%20IM%20)%5Cright%7C%20Ag$

Given $E%20_%7B%20Cu%20%5E%7B2%2B%7D%20%2F%20Cu%20%7D%5E%7B%5Ccirc%7D%20%3D0.337$
$E%20_%7B%20Ag%20%5E%7B%5Ccirc%7D%7D%7B%20Ag%20%7D%20%3D0.799$

Cell reaction

$Cu%20%2B2%20Ag%20%5E%7B%2B%7D%20%5Clongrightarrow%20Cu%20%5E%7B2%2B%7D%2B2%20Ag$
$E%3DE%5E%7B%5Ccirc%7D_%7BAg%5E%7B%2B%7D%2FAg%7D%20-E%5E%7B%5Ccirc%7D_%7BCu%5E%7B2%2B%7D%2FCu%7D%20-%20%5Cfrac%7B0.0591%7D%7B2%7D%20log%20%5Cfrac%7BCu%5E%7B2%2B%7D%7D%7B%5Cleft(Ag%5E%7B%2B%7D%5Cright)%5E%7B2%7D%7D$
$E%20%3D%200.799-0.337-%5Cfrac%7B0.0591%7D%7B2%7D%20%5Clog%20%5Cleft(%5Cfrac%7B%20l%20%7D%7B%20l%20%5E%7B2%7D%7D%5Cright)$
$E%20%3D%200.462%5C%2C%20V$

(iii) $Zn%20%5Cleft%7C%20Zn%20%5E%7B2%2B%7D(1%20M%20)%5Cright%7C%5Cleft%7C%20Co%20%5E%7B2%2B%7D(1%20M%20)%5Cright%7C%20Co$

Given, $E%20_%7B%20Zn%20%5E%7B2%2B%7D%20%2F%20Zn%20%7D%5E%7B%5Ccirc%7D%3D-0.762%20%3B%20E%20_%7B%20Co%20%5E%7B2%2B%7D%20%2F%20Co%20%7D%5E%7B%5Ccirc%7D%3D-0.277$

Cell reaction $%3A%20Zn%20%2B%20Co%20%5E%7B2%2B%7D%20%5Clongrightarrow%20Zn%20%5E%7B2%2B%7D%2B%20Co$
$E%20%3D%20E%20%5E%7B%5Ccirc%7D%20Co%20%5E%7B2%2B%7D%20%2F%20Co%20%5E%7B-%20E%20%5E%7B%5Ccirc%7D%20Zn%20%5E%7B2%2B%7D%20%2F%20Zn%20%7D-%5Cfrac%7B0.059%20l%20%7D%7B2%7D%20%5Clog%20%5Cleft%5B%5Cfrac%7B%20Zn%20%5E%7B2%2B%7D%7D%7B%20Co%20%5E%7B2%2B%7D%7D%5Cright%5D$
$E%20%3D-0.277-(-0.762)-%5Cfrac%7B0.0591%7D%7B2%7D%20%5Clog%20%5Cleft%5B%5Cfrac%7B1%7D%7B1%7D%5Cright%5D$
$E%20%3D0.485%5C%2C%20V$

(iv) $Zn%20%5Cleft%7C%20Zn%20%5E%7B2%2B%7D(1%20M%20)%20%5C%7C%20Cu%20%5E%7B2%2B%7D(%20lM%20)%5Cright%7C%20Cu$

Given, $E%20_%7B%20Zn%20%5E%7B2%2B%7D%20%2F%20Zn%20%7D%5E%7B%5Ccirc%7D%3D-0.762$
$E%20%5E%7B%5Ccirc%7D%20Cu%20%5E%7B2%2B%7D%20%2F%20Cu%20%5E%7B2%7D%3D0.337$

Cell reaction $Zn%20%2B%20Cu%20%5E%7B2%2B%7D%20%5Clongrightarrow%20Zn%20%5E%7B2%2B%7D%2B%20Cu$
$E%20%3D%20E%20%5E%7B%5Ccirc%7D%7B%20Cu%20%5E%7B2%2B%7D%20%2F%20Cu%20%7D-%20E%20%5E%7B%5Ccirc%7D%20Zn%20%5E%7B2%2B%7D%20%2F%20Zn%20%5E%7B-%7D%20%5Cfrac%7B0.059%20l%20%7D%7B2%7D%20%5Clog%20%5Cleft%5B%5Cfrac%7B%20Zn%20%5E%7B2%2B%7D%7D%7B%20Cu%20%5E%7B2%2B%7D%7D%5Cright%5D$
$E%20%3D0.337-(-0.762)-%5Cfrac%7B0.0591%7D%7B2%7D%20%5Clog%20%5Cleft(%5Cfrac%7B1%7D%7B%20l%20%7D%5Cright)$
$E%20%3D1.099$

Hence, cell B has maximum emf.

So, the correct answer is (B): $Zn%20%5Cleft%7C%20Zn%20%5E%7B2%2B%7D(1%20M%20)%20%5C%7C%20Ag%20%5E%7B%2B%7D(1%20M%20)%5Cright%7C%20Ag$

High-Yield Trend

Chapter Questions
1 MCQs

Official Solution

Nernst Equation

High-Yield Trend

Chapter Questions 1 MCQs

Official Solution

Chapter Questions
1 MCQs