Projectile Motion

In order to obtain maximum range the body should be projected at an angle of

45%5E%7B%5Ccirc%7D

. Horizontal range = horizontal velocity

%5Ctimes

time

H%20%3D

Height

R%20%3D

Range

R%3Du_%7Bx%7D%20%5Ctimes%20T

R%3D(u%20%5Ccos%20%5Ctheta)%20%5Ctimes%20%5Cfrac%7B2%20u%20%5Csin%20%5Ctheta%7D%7Bg%7D

R%3D%5Cfrac%7Bu%5E%7B2%7D%202%20%5Csin%20%5Ctheta%20%5Ccos%20%5Ctheta%7D%7Bg%7D

R%3D%5Cfrac%7Bu%5E%7B2%7D%20%5Csin%202%20%5Ctheta%7D%7Bg%7D

For maximum horizontal range,

2%20%5Csin%202%20%5Ctheta%3D1

%5Ctherefore%20%5Ctheta%3D45%5E%7B%5Ccirc%7D

%5Ctherefore%20400%3D%5Cfrac%7Bu%5E%7B2%7D%7D%7Bg%7D

...(i) Also, maximum height of projectile is

H%3D%5Cfrac%7Bu%5E%7B2%7D%20%5Csin%20%5E%7B2%7D%20%5Ctheta%7D%7B2%20g%7D%3D%5Cfrac%7Bu%5E%7B2%7D%20%5Csin%20%5E%7B2%7D%2045%5E%7B%5Ccirc%7D%7D%7B2%20g%7D

%3D%5Cfrac%7B400%7D%7B2%7D%20%5Ctimes%20%5Cfrac%7B1%7D%7B2%7D%3D100%5C%2C%20m

Chapter Questions
1 MCQs