Time Work

Given: - A and B together complete the work in 8 days. - A alone completes the work in 12 days. Step 1: Work done per day by A: Step 2: Work done per day by A and B together: Step 3: Work done per day by B: Taking LCM of 8 and 12, which is 24:
Thus, B alone takes 24 days to complete the work.

Let: - Work done by 1 man per day = - Work done by 1 boy per day = Given: 1. 2 men and 5 boys finish the work in 4 days: 2. 3 men and 6 boys finish the work in 3 days: Solving: Multiply the first equation by 3 and the second by 2: Subtracting: Substituting into :
Thus, one man alone will take:
Thus, the correct answer is 18 days.

Given: - Tap A fills in 12 hours → Rate = - Tap B fills in 12 hours → Rate = - Tap C empties in 8 hours → Rate = Total rate when all taps are open: Convert to a common denominator (LCM = 24): Time required to fill the tank:
Thus, the correct answer is 24 hours.