Motion In A Straight Line

Here,
Length of bridge,
Time taken by train to cross the bridge,
Let the length of the train be m.

or , or ,

Here,

Let = time at which body is at height
or , or

As,
Here,

Given, height of tap from ground,

Time taken by first drop to reach the ground,

Now, if first drop falls at O s, and second drops at 1/2 s, then third drop will fall at 1 s as they fall on equal time interval.
At , distance covered by 2 drop is,

Height of the second drop from the ground,
=
= 5 -1.25 = 3.75 m.

Among the given graphs, the graph(a) represents uniform motion.

First, convert the speed to m/s: The car stops after 3 seconds, so the distance covered can be calculated using the equation of motion: Since the car stops, final speed , initial speed , and time . From the equation: Solving for : Now, using the equation for distance covered under uniform acceleration: Substitute the values: Thus, the distance covered before the car comes to rest is 22.5 m.

The given displacement equation is: This is a quadratic equation with a negative quadratic term, indicating that the displacement starts from a positive value and then decreases as time progresses, forming a downward parabola. The motion described by this equation is represented by the graph in option (B), which shows a downward curve. Therefore, the correct answer is (B).