Alphabet Series

Step 1: Reverse the second half of the alphabet.
The second half of the alphabet is: $M%2C%20N%2C%20O%2C%20P%2C%20Q%2C%20R%2C%20S%2C%20T%2C%20U%2C%20V%2C%20W%2C%20X%2C%20Y%2C%20Z$ Reversing this gives: $Z%2C%20Y%2C%20X%2C%20W%2C%20V%2C%20U%2C%20T%2C%20S%2C%20R%2C%20Q%2C%20P%2C%20O%2C%20N%2C%20M$

Step 2: Construct the new series.
The modified series becomes: $A%2C%20B%2C%20C%2C%20D%2C%20E%2C%20F%2C%20G%2C%20H%2C%20I%2C%20J%2C%20K%2C%20L%2C%20Z%2C%20Y%2C%20X%2C%20W%2C%20V%2C%20U%2C%20T%2C%20S%2C%20R%2C%20Q%2C%20P%2C%20O%2C%20N%2C%20M$

Step 3: Find the twelfth letter and the seventh letter to the right of it.
The twelfth letter from the left end is $L$ . Counting seven letters to the right of $L$ , we get: $Z%2C%20Y%2C%20X%2C%20W%2C%20V%2C%20U%2C%20T$ Thus, the seventh letter to the right of $L$ is $U$ . Therefore, the correct answer is 3. U.

High-Yield Trend

Chapter Questions
1 MCQs

Official Solution

Alphabet Series

High-Yield Trend

Chapter Questions 1 MCQs

Official Solution

Chapter Questions
1 MCQs