Friction

We can calculate the force acting on the block and compare the forces: The gravitational force parallel to the inclined plane is:

F_%7B%5Ctext%7Bgravity%7D%7D%20%3D%20mg%20%5Csin(%5Ctheta)

Where: -

m%20%3D%202%20%5C%2C%20%5Ctext%7Bkg%7D

, -

g%20%3D%209.8%20%5C%2C%20%5Ctext%7Bm%2Fs%7D%5E2

, -

%5Ctheta%20%3D%2030%5E%5Ccirc

. The frictional force is:

F_%7B%5Ctext%7Bfriction%7D%7D%20%3D%20%5Cmu%20mg%20%5Ccos(%5Ctheta)

Where: -

%5Cmu%20%3D%200.2

(coefficient of friction). Now, calculating the forces:

F_%7B%5Ctext%7Bgravity%7D%7D%20%3D%202%20%5Ctimes%209.8%20%5Ctimes%20%5Csin(30%5E%5Ccirc)%20%3D%209.8%20%5C%2C%20%5Ctext%7BN%7D

F_%7B%5Ctext%7Bfriction%7D%7D%20%3D%200.2%20%5Ctimes%202%20%5Ctimes%209.8%20%5Ctimes%20%5Ccos(30%5E%5Ccirc)%20%5Capprox%203.4%20%5C%2C%20%5Ctext%7BN%7D

Since the force due to gravity is greater than the frictional force, the block will slide down the plane.

Chapter Questions
1 MCQs