Inorganic Chemistry

In HSO , the oxidation state of sulfur is +6, as determined by balancing the oxidation states of the other atoms in the ion.

Let's evaluate each option: - (a) HF is the strongest hydrohalic acid: This statement is correct, HF is a stronger acid than other hydrohalic acids due to the high electronegativity of fluorine. - (b) F is the strongest reducing agent among all types of halogen: This is incorrect, as fluorine is the strongest oxidizing agent, not a reducing agent. - (c) The order of -ve electron gain enthalpy for halogens is F > Cl > Br > I: This is incorrect because the electron gain enthalpy decreases down the group due to increasing atomic size.
So, I > Br > Cl > F. - (d) F has lower bond dissociation energy than Cl : This is correct.
Fluorine has a lower bond dissociation energy compared to chlorine because the bond in F is weaker due to electron-electron repulsion in the small fluorine molecule.
Thus, the correct answer is (d).

B₃N₃H₆, also known as inorganic benzene, is a molecule that resembles benzene in structure and bonding but consists of boron and nitrogen atoms rather than carbon atoms.
It is often called inorganic benzene due to its similar bonding to the structure of benzene.

To determine the D-configuration, we observe the orientation of the hydroxyl group (-OH) relative to the carbon atom. The D-configuration is given when the hydroxyl group is on the right-hand side of the Fischer projection. Thus, the compounds that have D-configuration are 5 and 15.

Catalysts speed up the reaction by lowering the activation energy, but they do not shift the position of the equilibrium. Catalysts provide an alternative pathway for the reaction, but they do not change the equilibrium constant. Thus, the correct answer is (d) catalysts shift the reaction equilibrium to the right.

and are tetrahedral complexes because the ligands (CN⁻ and CO) are small and can form stable tetrahedral coordination structures with the central metal ion, nickel (Ni). On the other hand, adopts a square planar geometry. This difference in coordination geometry is due to the nature of the ligands and the electronic configuration of the central metal ion, which influences the overall geometry of the complex.

Therefore, the correct option is (3).