Sections Of A Cone

The correct answer is B:7
Given that:
Equation of hyperbola is;

⇒

Focii is (±ae,0) or (±3,0)
Now for ellipse,
i.e,
,then by considering eccentricity ‘e’,focii is (±4e,0)
as focii ellipse and hyperbola coincides each with other
then; 4e=3
⇒
for ellipse
⇒
⇒