To determine the hybridization of nitrogen in diethyl amine (C4H11N), we first examine the structure of the molecule. Diethyl amine has the formula CH3CH2NHCH2CH3. In this molecule, the nitrogen atom forms three sigma bonds: two with carbon atoms and one with a hydrogen atom.
Hybridization is determined by the number of sigma bonds and lone pairs around the atom. The nitrogen in diethyl amine has:
- 3 sigma bonds (2 with carbon and 1 with hydrogen).
- 1 lone pair of electrons.
The total is 4, indicating sp3 hybridization. This is because:
- 1 s orbital and 3 p orbitals combine to form 4 equivalent sp3 hybrid orbitals.
Therefore, the hybridization of nitrogen in diethyl amine is sp3.