Logarithmic Differentiation

Let $y%20%3D%20log(sec%5C%20e%5E%7Bx%5E2%7D)$
$%5Cfrac%20%7Bdy%7D%7Bdx%7D%3D%20%5Cfrac%20%7Bd%7D%7Bdx%7D%20%5Blog(sec%5C%20e%5E%7Bx%5E2%7D)%5D$

$%5Cfrac%20%7Bdy%7D%7Bdx%7D%3D$ $%5Cfrac%20%7B1%7D%7Bsec(e%5E%7Bx%5E2%7D)%7D.%5Cfrac%20%7Bd%7D%7Bdx%7D%20%5Bsec%5C%20e%5E%7Bx%5E2%7D%5D$

$%5Cfrac%20%7Bdy%7D%7Bdx%7D%3D$ $%5Cfrac%20%7B1%7D%7Bsec(e%5E%7Bx%5E2%7D)%7D.%20%5Bsec%5C%20e%5E%7Bx%5E2%7D%5D$ $tan%5C%20e%5E%7Bx%5E2%7D.%20%5Cfrac%20%7Bd%7D%7Bdx%7D%20(e%5E%7Bx%5E2%7D)$
$%5Cfrac%20%7Bdy%7D%7Bdx%7D%3D$ $tan%5C%20(e%5E%7Bx%5E2%7D).e%5E%7Bx%5E2%7D.%5Cfrac%20%7Bd%7D%7Bdx%7D(x%5E2)$
$%5Cfrac%20%7Bdy%7D%7Bdx%7D%3D$ $tan%5C%20(e%5E%7Bx%5E2%7D).e%5E%7Bx%5E2%7D.2x$
$%5Cfrac%20%7Bdy%7D%7Bdx%7D%3D$ $2x.e%5E%7Bx%5E2%7D.tan%5C%20(e%5E%7Bx%5E2%7D)$

So, the correct option is (C): $2x.e%5E%7Bx%5E2%7D.tan%5C%20(e%5E%7Bx%5E2%7D)$

High-Yield Trend

Chapter Questions
1 MCQs

Official Solution

Logarithmic Differentiation

High-Yield Trend

Chapter Questions 1 MCQs

Official Solution

Chapter Questions
1 MCQs