Speed Time And Distance

To solve this problem, we need to determine the relationship between the variables given: the boy's speed before reduction (p km/h), the reduction in speed due to slippery ground (q km/h), and the time taken to cover the distance (r hours).

The boy's effective speed after reduction is (p - q) km/h. Given that the boy covers a distance of 1 km, we can use the formula:

Time = Distance / Speed

Substituting the given values into this equation, we have:

r = 1 / (p - q)

Rearranging the equation, we get:

1 / r = (p - q)

Thus, the correct condition is that the reciprocal of the time taken is equal to the effective speed after reduction, which matches the option:

• Length of train (Distance) = 300 m
• Speed of train = 60 km/h

• Distance = 180 meters
• Time = 6 seconds

1. Current Time: 10:40 am
2. Flight Schedule: Flights leave every 5 hours.
3. Previous Flight: Took off 25 minutes ago.
4. Calculate the time the last flight took off: 10:40 am - 25 minutes = 10:15 am.
5. Calculate the next flight time: Add 5 hours to 10:15 am.
6. 10:15 am + 5 hours = 3:15 pm.

Amit completes the race in 20 seconds, so his speed is:

Speed of Amit = .

Rahul completes the race in 25 seconds, so his speed is:

Speed of Rahul = .

In 20 seconds, Rahul covers:

Distance covered by Rahul = Speed of Rahul Time = .

The distance by which Amit beats Rahul is:

Distance = .

Thus, Amit beats Rahul by 140 m.

We are given:

Speed in still water ,
Speed of stream ,
Additional time taken upstream = 20 minutes = hours.

The effective speeds are:

Speed Upstream = ,
Speed Downstream = .

Let the distance between the two points be . The time taken for upstream and downstream travel is:

Time Upstream = ,
Time Downstream = .

The difference in time between upstream and downstream travel is:

.

Simplify the equation:

,
.

Multiply through by 21:

, .

Thus, the distance between the two points is 1.75 km.