Electromagnetic Waves

Step 1: Understanding the relation.
The electric field for an electromagnetic wave in a vacuum is related to the intensity of the wave by the equation: where is the permittivity of free space ( ), is the speed of light in vacuum ( ), and is the electric field.
Step 2: Applying the frequency relation.
For radiation with a frequency of , the electric field is determined based on the energy of the photons and the intensity of the radiation. Using the above formula, we find that the electric field magnitude will be approximately .
Step 3: Conclusion.
The correct answer is (C) .

Step 1: Understanding the Concept:
The Electromagnetic Spectrum is arranged by either increasing frequency or increasing wavelength. There is an inverse relationship between frequency and wavelength.
Step 2: Detailed Explanation:
Order of the EM spectrum (from longest wavelength to shortest): 1. Radio waves 2. Microwaves ( ) 3. Infrared 4. Visible light ( ) 5. Ultraviolet 6. X-rays ( ) 7. Gamma rays Therefore, (microwaves) is larger than (visible), which is larger than (X-rays).
Step 3: Final Answer:
The correct relation is .

Step 1: Understanding the Concept:
According to Maxwell's theory, an accelerating or oscillating charge produces electromagnetic waves.
Step 2: Detailed Explanation:
The frequency of the electromagnetic wave produced is exactly equal to the frequency with which the charged particle oscillates. Since the particle oscillates at Hz, the resulting EM wave will have the same frequency.
Step 3: Final Answer:
The frequency of the EM waves is Hz.