Equation Of A Line In Space

The equation of the plane through the line of intersection of the given planes is (x + y + z - 6) + (2x + 3y + 4z + 5) = 0 ... (1)
If equation (1) passes through (1, 1, 1), we have

Putting in (1), we obtain the
equation of the required plane as
(2x+3y+4z+5)=0
20x+23y+26z-69=0

Shortest distance PQ =
Now,

And


Shortest distance

The given equation of curve is :

which can be written as :


Put and
On comparing
Length of focus from vertex,
At focus and


Focus is