Inorganic Chemistry

Step 1: Identify oxidation states.

Mn%3A%20%2B7%20%5Crightarrow%20%2B4%20%5Cquad%20(%5Ctext%7Breduction%7D)

Br%3A%20-1%20%5Crightarrow%20%2B5%20%5Cquad%20(%5Ctext%7Boxidation%7D)

Step 2: Write half-reactions in basic medium. Reduction half-reaction:

MnO_4%5E-%20%2B%202H_2O%20%2B%203e%5E-%20%5Crightarrow%20MnO_2%20%2B%204OH%5E-

Oxidation half-reaction:

Br%5E-%20%2B%206OH%5E-%20%5Crightarrow%20BrO_3%5E-%20%2B%203H_2O%20%2B%206e%5E-

Step 3: Equalize electrons by multiplying the reduction half-reaction by 2.

2MnO_4%5E-%20%2B%204H_2O%20%2B%206e%5E-%20%5Crightarrow%202MnO_2%20%2B%208OH%5E-

Step 4: Add the two half-reactions and cancel common terms.

2MnO_4%5E-%20%2B%20Br%5E-%20%2B%20H_2O%20%5Crightarrow%202MnO_2%20%2B%20BrO_3%5E-%20%2B%202OH%5E-

Step 5: Hence, the coefficients of

MnO_4%5E-

BrO_3%5E-

, and

OH%5E-

are:

%5Cboxed%7B2%2C%5C%3B1%2C%5C%3B2%7D

Chapter Questions
1 MCQs