Sulphur

Sulphur burns in oxygen according to the following equation

%5Cunderset%7B32%20g%7D%7B%20S%20%7D%2B%20O%20_%7B2%7D%20%5Clongrightarrow%20SO%20_%7B2%7D%2B%5CDelta%20H_%7Bf%7D

0.5%5C%2C%20g

S liberate

%3D4.6%20%5C%2CkJ

heat

1%5C%2C%20g%20%5C%2CS

liberate

%3D%5Cfrac%7B4.6%7D%7B0.5%7D%20kJ

32%5C%2C%20g%20%5C%2CS

will liberate

%3D%5Cfrac%7B4.6%7D%7B0.5%7D%20%5Ctimes%2032

%3D294.4%20%5C%2CkJ

Heat of formation is the amount of heat liberated or absorbed when one mole of compound is formed from its constituent elements hence, Heat of formation of

SO%20_%7B2%7D%3D-294.4%5C%2C%20kJ

High-Yield Trend

Chapter Questions
1 MCQs

Official Solution

Sulphur

High-Yield Trend

Chapter Questions 1 MCQs

Official Solution

Chapter Questions
1 MCQs