Polynomials

Given equation can be rearranged as

x(x⁶ + 3x⁴ - 13x² - 15) = 0

Clearly x = 0 is one of the roots and the other part can be observed by replacing x² = t, from which we get:

t³ + 3t² - 13t - 15 = 0

⇒ (t - 3)(t² + 6t + 5) = 0

So, t = 3, t = -1, t = -5

Now we are getting:

x² = 3, x² = -1, x² = -5

⇒ x = ±√3, x = ±i, x = ±√5i

From the given condition:

|α₁| ≥ |α₂| ≥ .... ≥ |α₆|

We can clearly say that:

|α₁| = 0 and |α₂| = √5 = |α₅| and |α₄| = √3

= |α₃| and |α₂| = 1 = |α₁|

So we can have:

α₁ = √5i, α₂ = -√5i, α₃ = √3i, α₄ = √3, α₅ = i, α₆ = -i

Hence

α₁ - α₂ - α₃ + α₄ + α₅ + α₆ = 1 - (-3) + 5 = 9