Haloalkanes And Haloarenes

Answer:

Biphenyl (C₆H₅–C₆H₅)

Explanation:

When chlorobenzene is treated with sodium metal in dry ether, it undergoes the **Wurtz–Fittig reaction**.

2 C₆H₅Cl + 2 Na ⟶ C₆H₅–C₆H₅ + 2 NaCl

The product formed is biphenyl.

An allylic halide is an organic compound in which the halogen atom (X) is attached to a carbon atom that is adjacent to a carbon–carbon double bond (C=C).

The general formula of an allylic halide is: where the –CH₂–X group is attached to the carbon next to the double bond.

Let's analyze each option:

• (A) R–CH(X)–R → Halogen is on a saturated carbon (no double bond nearby); not allylic.
• (B) CH₂=CH–X → Halogen is directly bonded to a double-bonded carbon; this is a vinylic halide.
• (C) C₆H₅–X → Halogen is attached to an aromatic ring carbon; this is an aryl halide.
• (D) CH₂=CH–CH₂–X → Halogen is on the carbon adjacent to C=C; this is an allylic halide.

Therefore, the correct answer is: