Conductance

To determine the molar ionic conductance at infinite dilution ( ) for Ba(OH) , we analyze the dissociation of Ba(OH) into its constituent ions and utilize the given conductance values for related compounds.

1. Dissociation of Compounds:
   NaOH → Na + OH
   NaCl → Na + Cl
   BaCl → Ba + 2Cl
2. Equations for Molar Ionic Conductances:
   
   
   
3. Substituting the Given Values:
   248.1 × 10 = (1)
   126.5 × 10 = (2)
   280.0 × 10 = (3)
4. Solving for Individual Ionic Conductivities:
   Step 1: Subtract equation (2) from equation (1) to find :
   
   
   Step 2: Let:
   
   From equation (2): (4)
   From equation (1): (5)
   From the difference: (6)
   Step 3: Solve for and :
   (7)
   Substitute equation (7) into equation (5):
   
   (From equation (4))
   Step 4: From equation (3): (8)
5. Calculating for Ba(OH) :
   The dissociation of Ba(OH) is:
   Ba(OH) → Ba + 2OH
   Therefore:
   
   From the given correct answer and the context, we sum the conductances:
   

Therefore, the molar ionic conductance at infinite dilution for Ba(OH) is 523.2 × 10 S m mol .