Organic Chemistry

In this reaction, reacts with X (a carbonyl group) to reduce the carbonyl group to a secondary alcohol. Then, further reaction with and converts the alcohol group to a hydroxy group, leading to the product Y.

The reaction involves the reduction of cyclohexanone using , which reduces the carbonyl group to a hydroxyl group, resulting in compound A. The hydrogenation of A with reduces the double bond, forming compound B, a cyclohexane derivative.

• reactions are unimolecular with first-order kinetics, while reactions are bimolecular.
• reactions occur with inversion of configuration, while reactions do not involve the formation of a carbocation.
• reactions are favored by poor nucleophiles.

Step 1: Geranial and Neral.
Geranial and Neral are indeed geometrical isomers of citral, as they differ only in the orientation of the double bond at the aldehyde group. Hence, statement (A) is correct.

Step 2: Formation of Geranic acid.
Citral, on heating with potassium hydrogen sulfate, undergoes dehydration to form geranic acid, so statement (B) is also correct.

Step 3: Formation of 6-methylhept-5-en-2-one.
Citral does not form 6-methylhept-5-en-2-one when treated with potassium carbonate, making statement (C) incorrect.

Step 4: Oxidation to Laevolic acid.
On oxidation with silver oxide, citral undergoes cleavage to form Laevolic acid, making statement (D) correct.

Final Answer:

Step 1: Carbocation Stability.
The stability of a carbocation increases with the degree of alkyl substitution and resonance stabilization. The most stable carbocation is the one with the highest resonance stabilization.

Step 2: Analysis of Options.
- (C) - is the most stable due to resonance stabilization with the aromatic ring.
- (A) - is slightly less stable than (C) because the methyl group in (C) offers more stabilization.
- (D) - has less resonance stabilization.
- (B) - is the least stable.

Step 3: Conclusion.
Thus, the correct order of decreasing stability is (C), (A), (D), (B).

Final Answer: