Logic Gates

Step 1: OR gate output. Output is A+B.
Step 2: NAND with same inputs. Y = (A+B)(A+B) = A+B
Step 3: Conclusion. This is NOR gate behaviour.

Step 1: Oscillator feedback.
An oscillator requires positive feedback to sustain its oscillations. Positive feedback amplifies the signal and reinforces the oscillations.
Thus, the correct answer is (1).

Step 1: Analyze the given circuit.
The circuit is a combination of logic gates. An OR gate produces a high output when any of its inputs are high.
Step 2: Conclusion.
The given circuit functions as an OR gate. Final Answer:

Step 1: The given combination is a standard XOR gate realization using NAND gates.
Step 2: Output is high only when inputs are different.

Step 1: Collector current:
Step 2: Base current:
Step 3: Input voltage:

Step 1: Understanding the Concept
According to De Morgan's Laws, the combination of inverted inputs followed by a specific gate can be simplified into a single basic logic gate.

Step 2: Key Formula or Approach
De Morgan's Theorem states: 1. 2.

Step 3: Detailed Explanation
1. The inputs are first passed through NOT gates, giving and . 2. These are then fed into a NAND gate. The output of a NAND gate is the inversion of the product of its inputs: 3. Using De Morgan's Law ( ): 4. Since the double inversion cancels out ( ): 5. The expression represents an OR gate.

Step 4: Final Answer
The combination yields an OR gate.