Coordination Compounds

is cuprarnmonium ion.

Answer (c) nitrosonium

is tetra ammine copper (II) sulphate.
has 1 unpaired electron. Hence, it is paramagnetic.

???????????????????[Z= atomic number,
????????????O.N. = Oxidation number,
????????C.N. = Coordination number]
??= 27 - 3 + 2 6 = 36

The incorrect statement is Option (A) Here's why: - Option A: A square planar complex of the type Mabcd, where a, b, c, and d are unidentate ligands, exhibits geometrical isomerism and exists in one cis-form and two trans-forms. - This is incorrect because a square planar complex with four different unidentate ligands (Mabcd) will not exhibit geometrical isomerism with one cis-form and two trans-forms. A square planar complex can only exhibit two forms (cis and trans) when it has two similar ligands, not four different ones. - Option B: [Co(NH_3)_5NO_2]Cl_2 exists in two forms, the red form and the yellow form, which are linkage isomers. - This statement is true because linkage isomerism arises when a ligand can coordinate to the metal center through different atoms. In this case, the nitrite (NO_2) can bind either through the nitrogen or the oxygen atom, resulting in different linkage isomers. - Option C: [Fe(CN)_6]^{3-} is called a Low spin complex. - This statement is true because [Fe(CN)_6]^{3-} is an octahedral complex with a low-spin configuration due to the strong field ligand CN^-. - Option D: Out of cis-[CrCl_2(ox)_2]^{3-} and trans-[CrCl_2(ox)_2]^{3-}, the trans isomer is optically inactive. - This statement is true because the trans isomer has a plane of symmetry and is therefore optically inactive, while the cis isomer lacks a plane of symmetry and can be optically active.

The compound is a coordination complex containing cobalt as the central metal ion, chlorine (Cl), nitrite (NO ), and ammonia (NH ) ligands. 1. Cobalt oxidation state: The cobalt ion in this complex is in the +3 oxidation state, as indicated by the ligands attached to it. - The oxidation state of cobalt is determined by the charges of the other ligands. Ammonia (NH ) is neutral, chloride (Cl) is , and nitrite (NO ) is also . Therefore, cobalt must have a oxidation state to balance the charges of the ligands. 2. Ligand naming: - Ammonia (NH ) is named as "ammine." - Chloride (Cl) is named as "chloro." - Nitrite (NO ) is a bidentate ligand that can bind through either the nitrogen or oxygen atom. In this case, the nitrogen atom of nitrite coordinates with cobalt, so it is named "nitrito-N." 3. IUPAC Naming: The IUPAC name follows the standard order of ligands: - First, we list the ammonia ligands as "triamine" because there are three ammonia molecules. - Next, we list the chloride ligands as "dichloro." - Finally, we list the nitrite ligand as "nitrito-N." - Since the metal ion is in the +3 oxidation state, we indicate it as "cobalt(III)." Thus, the correct IUPAC name of the complex is Triamminedichloridonitrito-N-cobalt(III).

- Facial isomerism occurs when three identical ligands are arranged in a facial position, i.e., forming a 90° angle on the same side of the coordination sphere. - Meridional isomerism occurs when three identical ligands are arranged in a meridional position, i.e., occupying positions around the coordination sphere forming an angle of 180°. - Option (A): The compound exhibits both Facial and Meridional isomerism. The water and nitrate ions can be arranged in these two distinct geometries, leading to different isomers. - Option (B): The complex does not show Facial and Meridional isomerism. It exhibits optical isomerism, as the ligands are chiral but there is no room for facial and meridional arrangements. - Option (C): The complex does not exhibit facial and meridional isomerism. The geometry does not allow such isomerism due to the arrangement of ligands. - Option (D): Similarly, is a coordination complex where the ligands are arranged symmetrically, but it does not exhibit facial or meridional isomerism.

- Statement (A) is correct. Cellulose does not reduce Fehling's solution or Tollens' reagent because it does not have the free aldehyde group needed to carry out the reduction. This is in contrast to reducing sugars like glucose, which can reduce these reagents. - Statement (B) is correct. When cellulose is heated with dilute H SO under pressure, it undergoes hydrolysis to produce D-glucose. - Statement (C) is correct. Cellulose is a straight-chain polysaccharide made up of -D-glucose units linked together by -glycosidic bonds. - Statement (D) is incorrect. The -glycosidic linkages in cellulose are between C of one glucose unit and C of the next glucose unit, not C . This is a key structural feature of cellulose.