Electrochemistry

Ostwald's dilution law holds good for weak electrolytes. Ammonium hydroxide is. a weak electrolyte while all others salts are strong electrolytes.

= 0.34 - 3.05 = - 2.71 V

According to Faraday's second law of electrolysis,

According to Faraday's second law :

Wt. of Cu deposited

The emf of the cell can be calculated using the Nernst equation: Where is the number of electrons transferred (here for the iron half-reaction), and is the reaction quotient. For the given cell: Substitute the given concentrations: Simplify the logarithm: Thus, the emf of the cell is 0.41V.

We can calculate the resistance offered by the conductivity cell using the relation: Where: - is the resistance, - is the distance between the electrodes (1.0 cm), - is the surface area of the electrodes (3.0 cm ), - is the molar conductivity of the solution (194.5 ohm cm per mole). Substitute the values into the formula: The resistance is 0.00171 ohms. Therefore, after calculating, the value closest to the given options is 34.27 ohms.

Corrosion of iron is a redox reaction that occurs in two half-reactions: an anodic reaction (oxidation) and a cathodic reaction (reduction). 1. Anodic reaction (oxidation): Iron atoms lose electrons (oxidation) and are converted into ions. This reaction occurs at the anodic area of the iron rod: 2. Cathodic reaction (reduction): Oxygen from the air reacts with water and electrons to form hydroxide ions ( ) at the cathodic area: This reaction represents the reduction half-reaction at the cathode. 3. Overall reaction: The overall corrosion reaction involves the iron reacting with oxygen and water to form iron(III) hydroxide, which can eventually lead to rust: This corrosion process occurs in the presence of oxygen and water, and the reaction at the cathode is correctly represented in option (B). Thus, the correct statement is (B).