Precipitation

We are given the following information: - Volume of AgNO₃ solution = 150 ml - Concentration of AgNO₃ = 32% - Volume of NaCl solution = 150 ml - Concentration of NaCl = 11% - Molar mass of AgNO₃ = 108 g/mol (for Ag) - Molar mass of NaCl = 23 g/mol (for Na) + 35.5 g/mol (for Cl) = 58.5 g/mol First, we need to calculate the amount of Silver nitrate (AgNO₃) and Sodium chloride (NaCl) in moles: Since Silver chloride (AgCl) precipitates in a 1:1 molar ratio between Ag⁺ and Cl⁻, the limiting reactant will determine the amount of AgCl that forms. Now, calculate the mass of AgCl: Thus, the mass of Silver chloride precipitated is 40.47 g.