Molality And Molarity

The molarity (M) is given by: The number of moles of CaCl is calculated as: Thus, the molarity is: Thus, the correct answer is Option (A).

To calculate the molality ( ) of the sulphuric acid, we can use the formula: Where: - is the number of moles of solute, - is the mass of the solvent in kilograms. We are given: - The molarity ( ) of the solution is 4.5 M, which means 4.5 moles of H SO are present in 1 liter of solution. - The density ( ) of the solution is 1.28 g/ml, which is equivalent to 1280 g/L. The mass of the solution is: The mass of the solute (H SO ) is: The mass of the solvent (water) is: Now, we can calculate the molality ( ):
Thus, the molality of the acid is 5.364 mol/kg.