Ideal Gas Equation

Step 1: Understanding the Graph Relationship
For an ideal gas, the equation is:

PV%20%3D%20nRT

Rearranging in the form of a straight line equation:

P%20%3D%20%5Cfrac%7BnRT%7D%7BV%7D

which can be rewritten as:

P%20%3D%20(nR%20T)%20%5Ctimes%20V%5E%7B-1%7D

Comparing with the equation of a straight line

y%20%3D%20mx%20%2B%20c

, we see that the slope of the graph is equal to

nRT

.
Step 2: Calculating Temperature
Given that: - Slope

%3D%2032.8

L atm mol

%5E%7B-1%7D

n%20%3D%201

(one mole of gas)
-

R%20%3D%200.0821

L atm mol

%5E%7B-1%7D

%5E%7B-1%7D

Using:

%5Ctext%7BSlope%7D%20%3D%20nRT

32.8%20%3D%20(1)%20%5Ctimes%20(0.0821)%20%5Ctimes%20T

Solving for

T

T%20%3D%20%5Cfrac%7B32.8%7D%7B0.0821%7D

T%20%3D%20400%20%5Ctext%7B%20K%7D

Final Answer: The correct temperature is

400

K, which matches Option (4).

Chapter Questions
1 MCQs