In the circuit shown in the figure, neglecting the source resistance, the voltmeter and ammeter readings respectively are:
1
2
3
4
Official Solution
Correct Option:
(1)
Step 1: Determine total impedance in the circuit The given circuit consists of a resistor in series with a parallel LC circuit, where the inductor reactance is and the capacitor reactance is . Since , the net reactance of the LC branch is: Thus, the LC branch acts as a short circuit, meaning the impedance of the parallel combination is zero. Step 2: Calculate total circuit current The only effective impedance in the circuit is the resistor , so the total impedance is: Using Ohm’s law, the current through the circuit is: Step 3: Determine the voltmeter reading Since the LC branch is a short circuit, the voltage across the parallel LC circuit (voltmeter reading) is: Final Answer: The ammeter reads and the voltmeter reads , which matches option (1).
About Ac Circuits - AP-EAMCET
Ac Circuits is a vital chapter for AP-EAMCET aspirants. Mastering the concepts covered in this chapter is essential for securing a top rank.
By rigorously practicing the previous year questions associated with this chapter, you can identify high-yield topics, understand the examiner's perspective, and boost your confidence during the actual exam.
Frequently Asked Questions
Why focus on Ac Circuits PYQs?
Analyzing PYQs for this specific chapter reveals the most frequently tested concepts and the typical complexity of questions, allowing you to tailor your study plan efficiently.
How to best use this analysis?
Review the topic breakdown to see which sub-topics within Ac Circuits carry the most weight. Then, tackle the questions iteratively to solidify your understanding.
