When an AC source of EMF with frequency = 100 Hz is connected across a circuit, the phase difference between and current in the circuit is observed to be as shown in the figure. If the circuit consists of only RC or RL in series, then
Given: - Frequency of AC source: - Phase difference between EMF and current : - Circuit is either an RC or RL series circuit
Case 1: RC Circuit In an RC circuit, phase angle is given by: Given Angular frequency: Resistance Now, calculate : Approximating : So for , let's verify: This does **not** match the condition
Case 2: RL Circuit In an RL circuit, phase angle is: Using same , so: But given options include and , neither of which satisfy the phase condition exactly.
For a domestic AC supply of 220 V at 50 cycles per sec, the potential difference between the terminals of a two-pin electric outlet in a room is given by
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Official Solution
Correct Option:
(1)
Concept: AC voltage form:
where and . Step 1: {\color{red}Given data.} Step 2: {\color{red}Find peak voltage.} Step 3: {\color{red}Angular frequency.} Step 4: {\color{red}Write expression.}
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