Capacitors And Capacitance

According to question

and
Solving, we get .

Step 1: Understanding the Circuit The capacitors are in parallel, and once the current becomes steady, the capacitors will be fully charged. 1. The voltage across each capacitor will be the same because they are in parallel. 2. The total voltage supplied in the circuit is 6V.
Step 2: Formula for Charge on a Capacitor The charge on a capacitor is given by the formula: Where: - is the capacitance, - is the voltage across the capacitor.
Step 3: Calculating the Charges We can now calculate the charge on each capacitor. 1. For the 1 µF Capacitor: 2. For the 2 µF Capacitor:
Step 4: Conclusion The charges stored in the capacitors are: - 6 µC in the 1 µF capacitor, - 12 µC in the 2 µF capacitor. However, the answer choices provided do not match the exact result of 6 µC and 12 µC. Based on the closest match, the correct answer is:

Concept:
At steady state, capacitors act as open circuits.

Step 1: Remove capacitors
Only resistive network remains.

Step 2: Equivalent resistance between A and B
Parallel:



Step 3: Voltage division
Total series with 1kΩ external gives equal division of 6 V.
So potential difference across AB = 3 V.

Step 4: Charges

For :

For :

Closest matching option ⇒ .