Wave Interference

The resulting intensity of two identical light waves, which have a phase difference of δ and propagate in the same direction, is

Therefore, the resulting intensity of the wave is directly proportional to
So, the correct option is (C) :

Given:
In a Young's double slit experiment, the intensity at a point on the screen where the path difference is is . We are asked to find the intensity at a point where the path difference is .

Step 1: Intensity Formula
The intensity of the light at any point on the screen is given by the formula: where is the maximum intensity, and is the path difference between the two interfering waves.

Step 2: Path Difference
When the path difference is , the intensity is at its maximum, i.e., . Therefore, the intensity at this point is:

Step 3: Path Difference
When the path difference is , we substitute into the intensity formula: Since , we have:

Answer: The intensity at a point where the path difference is is .

Given:
In Young's double slit experiment, the maximum intensity

Let the individual intensities of the two waves be:
and

Then, we use the formulas:

Given:

Taking square root on both sides:

Cross-multiplying:

Squaring both sides:

So, the ratio of intensities: Answer: 1/9