Quantum Mechanical Model Of Atom

The correct option is (B): .
The electron orbital,
n=4,I=2,
m=±2,
o and s=± .
Thus the correct answer is : 4, 2,1, 0

Given, velocity of particle
Velocity of particle
Let the mass of particle
The mass of particle
de-Broglie's equation is

For particle

For particle B

Eq (i)/(ii)


Or

Magnetic moment of is .
is in oxidation state having configuration of .
It has unpaired electrons.



Magnetic moment of is .
is in oxidation state having configuration of [Ar] 3d .
It has unpaired electrons.



Magnetic moment of is .
is in oxidation state having configuration of . In this complex ion is a strong ligand and all electrons are paired and there are no unpaired electrons.



The decreasing order of the magnetic moments is:

Step 1: Magnetic quantum number satisfies: ml = -l, … , +l
Step 2: Given ml=-3 ⟹ l=3.
Step 3: Principal quantum number: n ≥ l+1 = 4

The number of radial nodes of and orbitals respectively are and respectively.
Number of radial nodes
For orbital, number of radial nodes
For orbital, number of radial nodes

Step 1: Magnetic quantum number ml varies from: -l to +l
Step 2: Given ml = -3 ⟹ l ≥ 3.
Step 3: Azimuthal quantum number l ranges from: 0 to (n-1)
Step 4: Minimum value of n for which l=3 is: n=4