Laws Of Chemical Combinations

For I oxide Oxygen

~%3D36.4

%
Metal

%3D100-36.4%3D63.6%25

Given, formula of oxide

%3DM_%7B2%7DO

%5Ctherefore%2063.6%5C%25

of metal

%3D%202

atoms of metal
and

36.4%5C%25

of oxygen

%3D%201

atom of oxygen For II oxide Oxygen

%3D53.4%5C%25

Metal

%3D100-53.4%3D46.6%5C%25

%5Cbecause%2063.6%5C%25

of metal

%3D%202

atoms of metal

%5Ctherefore

46.6%5C%25

of metal

%3D%5Cfrac%7B2%5Ctimes%2046.6%7D%7B63.6%7D

%3D1.46

atoms of metal Again

%5Cbecause%2036.4%5C%25

of oxygen

%3D%201

atom of oxygen

%5Ctherefore

53.4%5C%25

of oxygen

%3D%5Cfrac%7B1%5Ctimes%2053.4%7D%7B36.4%7D

%3D1.46

atoms of oxygen Ratio of metal and oxide

%3D1.46%3A1.46

%3D1%3A1

Hence, formula of metal oxide

%3D%20MO

Chapter Questions
1 MCQs