Problem On Age

Step 1: Let the ages of A and B be and respectively, based on the given ratio.
Step 2: According to the problem, the sum of their ages is 72:
Step 3: Combine like terms:
Step 4: Solve for :
Step 5: Calculate B's age by multiplying by 5:
Hence, B's age is 40 years.

Step 1: Let the present ages be Step 2: After 5 years, the ratio is Step 3: Cross-multiply and solve for Step 4: Calculate A's present age

Step 1: Let the son's present age be years.
Then, man's present age = years.
Step 2: Five years ago, son's age = , man's age = .
Step 3: According to the problem, five years ago:
Step 4: Solve the equation:
Step 5: Son's present age years.
Man's present age = years.
Step 6: Check options: 20 years is not listed among options. This suggests the options might be incorrect or the question may have a typo. Step 7: Among given options, none exactly fits, but algebraic solution stands.

Let the present ages of Amit and his father be 2x and 5x, respectively.
After 4 years, their ages will be:

Given,

Cross multiply:




So present ages:

After 6 years, ages:

Ratio after 6 years:

Let the two-digit number be 10x + y, where x and y are digits.
Sum of number and reversed number:


Given the digits differ by 7:

Case 1: x - y = 7
From x + y = 9, add both equations:

Number is 81.
Case 2: y - x = 7
From x + y = 9, add:

Number is 18.
Thus, possible numbers are 81 and 18, but choosing 81 as the answer.