Phasor Diagrams

As the current i leads the emf e by

%5Cfrac%7B%5Cpi%7D%7B4%7D

, it is an R-C circuit

tan%20%5Cphi%20%3D%20%5Cfrac%7BX_c%7D%7BR%7D%20%5C%2C%20%5C%2C%20or%20%5C%2C%20%5C%2C%20tan%20%5Cfrac%7B%5Cpi%7D%7B4%7D%20%3D%20%5Cfrac%7B%5Cfrac%7B1%7D%7B%3F%20C%7D%7D%7BR%7D

%5Ctherefore%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%3F%20CR%20%3D%201

As%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%3F%20100%20rad%2Fs

The product of C-R should be

%5Cfrac%7B1%7D%7B100%7Ds%5E%7B-1%7D

%5Ctherefore

Correct answer is (a).

Chapter Questions
1 MCQs