Single Slit Diffraction

At first minima, b sin

%5Ctheta%20%3D%5Clambda

%5Chspace%7B10mm%7D%20b%20%5C%2C%20%5Ctheta%3D%5Clambda%20%5C%2C%20or%20%5C%2C%20%5C%2C%20b%20%5Cbig(%5Cfrac%7B%5Clambda%7D%7BD%7D%5Cbig)%3D%5Clambda

%5Chspace%7B25mm%7D%20y%3D%5Cfrac%7B%5Clambda%20D%7D%7Bb%7D

%5Chspace%7B25mm%7D%20%5Cfrac%7Byb%7D%7BD%7D%3D%5Clambda%20%5Chspace%7B20mm%7D%20...%20(i)

Now, at P (First minima) path difference between the rays
reaching from two edges (A and B ) will be

%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5CDelta%20x%3D%5Cfrac%7Byb%7D%7BD%7D%20%5Chspace%7B10mm%7D

(Compare with

%5CDelta%20x%3D%5Cfrac%7Byd%7D%7BD%7D

in YDSE)
or

%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5CDelta%20x%3D%5Clambda%20%5Chspace%7B30mm%7D

[From E (i)]
Corresponding phase difference

(%5Cphi)

will be

%5Chspace%7B15mm%7D%20%5Cphi%3D%5Cbig(%5Cfrac%7B2%20%5Cpi%7D%7B%5Clambda%7D%20%5Cbig)%2C%5CDelta%20x%2C%5Cphi%3D%5Cfrac%7B2%20%5Cpi%7D%7B%5Clambda%7D.%5Clambda%3D2%20%5Cpi

I(%5Cphi)%3DI_1%2BI_2%2B2%20%5Csqrt%7BI_1%20I_2%7D%20cos%20%5C%2C%20%5Cphi%20%5Chspace%7B20mm%7D%20...(i)

Here,

%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20I_1%3DI%20%5C%2C%20and%20%5C%2C%20I_2%3D4I

At point A,

%5Cphi%3D%5Cfrac%7B%5Cpi%7D%7B2%7D

%5Ctherefore%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20I_A%3DI%2B4I%3D5I

At point B,

%5Cphi%3D%5Cpi

%5Ctherefore%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20%5C%2C%20I_B%3DI%2B4I-4I%3DI

%5Ctherefore%20%5C%2C%20%5C%2C%20%5C%2C%20I_A-I_B%3D4I

NOTE E (i) for resultant intensity can be applied only when the
sources are coherent. In the question it is given that the rays
interfere. Interference takes place only when the sources are
coherent. That is why we applied equation number (i). When the
sources are incoherent, the resultant intensity is given by I =

I_1%2BI_2

About Single Slit Diffraction - JEE-ADVANCED

Single Slit Diffraction is a vital chapter for JEE-ADVANCED aspirants. Mastering the concepts covered in this chapter is essential for securing a top rank.

By rigorously practicing the previous year questions associated with this chapter, you can identify high-yield topics, understand the examiner's perspective, and boost your confidence during the actual exam.

Frequently Asked Questions

Why focus on Single Slit Diffraction PYQs?

Analyzing PYQs for this specific chapter reveals the most frequently tested concepts and the typical complexity of questions, allowing you to tailor your study plan efficiently.

How to best use this analysis?

Review the topic breakdown to see which sub-topics within Single Slit Diffraction carry the most weight. Then, tackle the questions iteratively to solidify your understanding.

High-Yield Trend

Chapter Questions
2 MCQs

Official Solution

Official Solution

About Single Slit Diffraction - JEE-ADVANCED

Frequently Asked Questions

Why focus on Single Slit Diffraction PYQs?

How to best use this analysis?

Single Slit Diffraction

High-Yield Trend

Chapter Questions 2 MCQs

Official Solution

Official Solution

About Single Slit Diffraction - JEE-ADVANCED

Frequently Asked Questions

Why focus on Single Slit Diffraction PYQs?

How to best use this analysis?

Chapter Questions
2 MCQs