Electronic Configurations Of Elements And The Periodic Table

The electronic configuration of palladium (Pd) with atomic number 46 is as follows:
- Palladium has a filled subshell and an empty and subshells in the ground state configuration.
- The correct configuration is , which reflects the stable, filled -subshell.

Thus, the correct answer is (C).

Germanium (Ge) is an element from Group 14 of the periodic table, which means it has 4 valence electrons. All elements in Group 14 (such as carbon, silicon, and germanium) have the same number of valence electrons. The number of valence electrons corresponds to the group number in the periodic table. Therefore, Germanium has 4 valence electrons, which can participate in bond formation.

The uncertainty principle, also known as Heisenberg's uncertainty principle, is a fundamental concept in quantum mechanics. It states that there is a limit to how precisely we can know both the position and the momentum of a particle simultaneously.

Step 1: Applicability of the uncertainty principle.
The uncertainty principle is significant for very small particles, such as subatomic particles (e.g., protons, electrons, etc.). For larger objects, such as molecules like methane or larger particles like platinum or NaCl crystals, the uncertainty in position and momentum is so small that it becomes negligible.

Step 2: Why proton is valid for the uncertainty principle.
The uncertainty principle is most relevant to elementary particles like protons, which are tiny and exhibit quantum mechanical effects. In such small particles, the uncertainty in the position and momentum is significant.

Step 3: Conclusion.
Therefore, the uncertainty principle is valid for protons, and the correct answer is (A) Proton.

Final Answer: (A) Proton

The atomic radius generally decreases as we move across a period from left to right in the periodic table. This happens because, as we move across a period, the number of protons increases, leading to a greater nuclear charge. The increased nuclear charge pulls the electrons closer to the nucleus, reducing the size of the atom.

Step 1: Atomic radius across the period.
- In the case of the elements in the question, we are dealing with period 2 elements: B (Boron), C (Carbon), N (Nitrogen), O (Oxygen), and F (Fluorine).
- As we move from left to right across the period, the atomic radius decreases.

Step 2: Atomic radius of fluorine.
Fluorine (F) is the rightmost element in the period, and therefore, it has the least atomic radius. This is because it has the highest effective nuclear charge in this period, which pulls its electrons closer to the nucleus.

Step 3: Conclusion.
Therefore, the element with the least atomic radius is fluorine (F), which corresponds to option (E).

Final Answer: (E) F