The Kinetic Theory Of Gases

First, find the moles of ethanol required: Now, calculate the mass of ethanol: Using the density formula, find the volume: Thus, the required volume of ethanol is 125 mL.

Carbocation stability follows the order tertiary > secondary > primary due to hyperconjugation and inductive effects.
- Tertiary carbocation is the most stable due to maximum hyperconjugation from three methyl groups.
- Primary carbocation is more stable than the secondary carbocation due to its structure.
- Secondary carbocation is the least stable due to minimal hyperconjugation.
Thus, the correct order is:

The reaction of HI with ethers follows acidic cleavage, where the more hindered alkyl group retains the OH, while the less hindered group forms an iodoalkane.
- The larger group (2-methylbutyl) forms 2-methylbutan-1-ol.
- The smaller group (ethyl) forms iodoethane.
Thus, the major products are 2-methylbutan-1-ol and iodoethane.

Ozonolysis of but-2-ene in the presence of water and zinc dust breaks the double bond, forming two carbonyl compounds. The further reduction of ozonolysis products gives ethanol.
- Step 1: Ozone cleaves the double bond, forming two aldehydes or ketones.
- Step 2: Reduction with Zn/H O converts one of the fragments into ethanol.
Thus, the correct reagent for this conversion is O /H O-Zn dust.

N,N-Dimethylmethanamine is commonly used as an insect attractant. It has a specific amine functional group that attracts certain insects, including moths, making it a useful compound in pest control.

Step 1: Understanding chirality
A molecule is chiral if it has at least one chiral center (a carbon attached to four different groups). A molecule is achiral if it lacks chirality, meaning it either has a plane of symmetry or does not have a chiral center.
Step 2: Analyzing each option
(A) 2-bromobutane: The carbon at position 2 is attached to four different groups, making it chiral.
(B) 3-nitropentane: - The carbon at position 3 is bonded to two identical ethyl ( ) groups. - Since it lacks four distinct groups, it is achiral.
(C) 3-chlorobut-1-ene: Has a potential chiral center.
(D) 1-bromoethanol: Contains a chiral carbon due to four different groups. (E) 2-hydroxypropanoic acid: Contains a chiral carbon at position 2.
Step 3: Conclusion The only molecule without a chiral center is 3-nitropentane. Hence, it is the achiral molecule.