Water

The formula for the boiling point elevation is:

Where:

• is the van't Hoff factor (number of particles the electrolyte dissociates into).
• is the ebullioscopic constant of the solvent (water in this case).
• is the molality of the solution.

Step 1: Calculate the molality of the solution.

Molality is defined as:

The number of moles of solute is:

Since the solvent mass is 1 kg, the molality is:

Step 2: Since the electrolyte dissociates into 3 ions ( and ), the van't Hoff factor .

Step 3: Now, calculate the change in boiling point:

Step 4: The normal boiling point of water is 373.15 K, so the new boiling point is:

Thus, the boiling point of the solution is .

In the electrolysis of water, the reaction is: From the reaction, 1 mole of O is produced by the passage of 4 moles of electrons.
The molar mass of O is 32 g. Therefore, the moles of O in 16 g are:
The charge required to produce 1 mole of O is 4 moles of electrons, which corresponds to: For 0.5 moles of O , the charge required is: Thus, the total charge required to liberate 16g of O is .

The combustion of cyclopropane ( ) can be represented by the following balanced chemical equation: This equation indicates that each mole of cyclopropane produces 3 moles of water ( ). First, calculate the molar mass of cyclopropane: Now, calculate the number of moles of cyclopropane: Using the stoichiometry of the reaction, the moles of water produced are three times the moles of cyclopropane: Thus, the correct answer is option (D), 1.0 mole.