Solubility Equilibria Of Sparingly Soluble Salts

We need to find the equilibrium where the change in the number of moles of gases (Δn_g) is zero.

1) $2NOCl(g)%20%E2%87%8C%202NO(g)%20%2B%20Cl_2(g)$
Reactants = 2 mol, Products = 2 + 1 = 3 mol ⇒ Δn_g = 3 - 2 = 1
2) $H_2(g)%20%2B%20Br_2(g)%20%E2%87%8C%202HBr(g)$
Reactants = 1 + 1 = 2 mol, Products = 2 mol ⇒ Δn_g = 2 - 2 = 0 ✅
3) $CO_2(g)%20%2B%20C(s)%20%E2%87%8C%202CO(g)$
Reactants = 1 mol, Products = 2 mol ⇒ Δn_g = 2 - 1 = 1
4) $Ni(s)%20%2B%204CO(g)%20%E2%87%8C%20Ni(CO)_4(g)$
Solids are not counted ⇒ Reactants = 4 mol, Products = 1 mol ⇒ Δn_g = 1 - 4 = -3
5) $N_2O_4(g)%20%E2%87%8C%202NO_2(g)$
Reactants = 1 mol, Products = 2 mol ⇒ Δn_g = 2 - 1 = 1

2) $H_2(g)%20%2B%20Br_2(g)%20%E2%87%8C%202HBr(g)$ (Δn_g = 0)

Chapter Questions
1 MCQs