Two parallel plates of area A are separated by two different dielectrics as shown in figure. The net capacitance is
1
2
3
4
Official Solution
Correct Option: (4)
Step 1: Formula
Net capacitance for dielectrics in series: . Step 2: Values
and . Step 3: Calculation
. Final Answer: (d)
02
PYQ 2011
medium
physicsID: met-2011
A 10 F capacitor is charged to a potential difference of 50 V and is connected to another uncharged capacitor in parallel. Now the common potential difference becomes 20 V. The capacitance of second capacitor is:
1
10 F
2
20 F
3
30 F
4
15 F
Official Solution
Correct Option: (4)
Step 1: Apply the principle of conservation of charge. When capacitors are connected in parallel, the total charge before and after connection is conserved. Initially, the charge on the 10 F capacitor is . Step 2: Set up the equation. After connection, the total charge is shared by both capacitors. The final potential difference across both capacitors is 20 V. Let be the capacitance of the second capacitor, then:
Substitute the known values:
Step 3: Conclusion. The capacitance of the second capacitor is 15 ΓΒ΅F, which is option (4).
03
PYQ 2013
medium
physicsID: met-2013
If the length of a pendulum is made 9 times and mass of bob is made 4 times, then the value of time period becomes
1
3T
2
3
4T
4
2T
Official Solution
Correct Option: (1)
Step 1: Understanding the Concept:
Time period of simple pendulum: . Independent of mass. Step 2: Detailed Explanation:
. New length .
.
Mass does not affect time period. Step 3: Final Answer:
Thus, new time period = 3T.
04
PYQ 2020
medium
physicsID: met-2020
Five equal capacitors each with capacitance are connected as shown in the figure. Then, the equivalent capacitance between and is:
1
2
3
4
Official Solution
Correct Option: (4)
Concept: β’ Capacitors in series:
β’ Capacitors in parallel: Step 1: Identify structure.
The circuit forms a bridge-like symmetric network. Step 2: Use symmetry.
Due to symmetry, the potential at middle junctions becomes equal. Hence, no charge flows through the central bridge capacitor. Step 3: Simplify circuit.
The network reduces to simple series-parallel combination:
β’ Left two capacitors combine
β’ Right two capacitors combine Step 4: Final reduction.
After simplification:
05
PYQ 2021
medium
physicsID: met-2021
Two capacitors of capacitance and are connected in series. A potential difference of 800 V is applied to the outer plates of the two capacitors system. The charge on each capacitor will be :
1
1200 C
2
6000 C
3
4
Official Solution
Correct Option: (4)
Concept:
For series capacitors:
Charge is same on each capacitor:
Step 1: Equivalent capacitance.
Step 2: Charge.
06
PYQ 2024
medium
physicsID: met-2024
In the following circuit diagram, potential difference across capacitor is:
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1
2
3
4
Official Solution
Correct Option: (4)
Concept: β’Capacitors in parallel:
β’Capacitors in series:
β’Same charge flows in series Step 1:Combine parallel capacitors:
Step 2:Now in series with :
Step 3:Total charge:
Step 4:Voltage across :